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Zinaida [17]
3 years ago
12

The area of a square sandbox is 83

Mathematics
1 answer:
elixir [45]3 years ago
8 0
The answer to this question is 36. The formula to find area of a square is a squared. By equating that formula to 83 and taking the square root of both sides, we get the value of one side which is 9.1. Then we multiply that value by 4 because all sides of a square have equal values. This our answer becomes 36.4 which is rounded to 36.
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Solve y/2 + 22 =38 for y
KATRIN_1 [288]

Answer:

y = 32

Step-by-step explanation:

\frac{y}{2}+22=38\\\frac{y}{2}=16\\y=32

4 0
2 years ago
Read 2 more answers
How do you solve this?​
blondinia [14]

Answer:

≈ 3.6 x 10^1

Step-by-step explanation:

= (6.05 x 3.05) x 10^(5+4) / (4.27 x 1.2) x 10^(4+4)

= 18.4525 x 10^9 / 5.124 x 10^8

= (18.4525 / 5.124) x 10^(9-8)

≈ 3.6 x 10^1

6 0
2 years ago
On the line you created from part A, mark a point D that is distinct from point C. Then, use the slope formula along with the co
ad-work [718]

The slope of AB and the slope of DC based on the information about the coordinate will be -2 and -2 respectively.

<h3>How to illustrate the information?</h3>

From the information given, we are told to use the slope formula along with the coordinates of points A, B, C, and D to find the slope.

The slope of AB based on the information will be:

= (-1 -3)/(-1 --3)

= -4/2

= 2

The slope of DC will be:

= 2-6/(1 --1)

= -4/2

= -2

Therefore, the slope of AB and the slope of DC based on the information about the coordinate will be -2 and -2 respectively.

Learn more about coordinate on:

brainly.com/question/11337174

#SPJ1

7 0
1 year ago
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
2 years ago
What is the solution to 3x + 2.4 ≥ 3.0​
vichka [17]
3x _> 3.0 - 2.4
= 3x _> 3/5
= 1/5
7 0
3 years ago
Read 2 more answers
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