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4 years ago

Greg and Lu are building a toy hydraulic crane, as shown in the picture.

Mathematics

2 answers:

iVinArrow [24]4 years ago

6 0

So,

Notice that there is a triangle with two of the angles given. We know that the sum of any triangle's angles will always be 180°. Thus, we can subtract the two given angles from 180, and that will give us the measure of angle ABC.

180 - 20 - 25 = 160 - 25 = 135

The measure of angle ABC is 135°.

The correct option is D.

Aleks [24]4 years ago

5 0

Answer:

Step-by-step explanation:

credit goes to the one that answered it

Notice that there is a triangle with two of the angles given. We know that the sum of any triangle's angles will always be 180°. Thus, we can subtract the two given angles from 180, and that will give us the measure of angle ABC.

180 - 20 - 25 = 160 - 25 = 135

The measure of angle ABC is 135°.

The correct option is D.

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On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

3 0

4 years ago

On a level field, a telephone pole 24 feet tall casts a shadow 6 feet long, and at the same time of day, another nearby telephon

nalin [4]

E. 72
6 feet long cast shadow = 24 feet pole
18 feet long cast shadow = 72 feet pole
18/6=3
24x3=72

5 0

4 years ago

Find the derivative of <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7B6%7D%7Bx%7D%20" id="TexFormula1" titl

aev [14]

$f'(x_0)=\lim\limits_{h\to0}\dfrac{f(x_0+h)-f(h)}{h}=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{6}{x};\ x_0=2\\\\subtitute\\\\f'(2)=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-\frac{6}{2}}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-3}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6-3x}{x}}{x-2}=\lim\limits_{x\to 2}\dfrac{6-3x}{x(x-2)}\\\\=\lim\limits_{x\to2}\dfrac{-3(x-2)}{x(x-2)}=\lim\limits_{x\to2}\dfrac{-3}{x}=-\dfrac{3}{2}=-1.5\\\\\\An swer:\boxed{f'(2)=-1.5}$

8 0

3 years ago

Can u help me please :)

GuDViN [60]

She has to go down 4, back up to 0, and then up another 4, then back to 0.If positive 1 represents the first level above ground, negative numbers are a good choice to represent levels below ground. 8 flights; starting at -4 and moving to 4.

7 0

3 years ago

Solve –4(6x + 3) = –12(x + 10).

Artist 52 [7]

–4(6x + 3) = –12(x + 10)
-24x - 12 = -12x - 120
24x - 12x = 120 - 12
12x = 108
x = 9

7 0

3 years ago

Read 2 more answers