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2 years ago

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For each set of angles name the angle pair and find the missing measurement Type of angle pair 2) These angles are to 1340 SO...

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1 answer:

AfilCa [17]2 years ago

3 0

Do not open that link above

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The diagram shows the net of a juice box. The box is a reactangular prism

dimaraw [331]

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3 years ago

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Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

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2 years ago

If tan a = 9／40<br>use trigonometric identities to find the values of sin a and cos a.

Sindrei [870]

Answer:

see explanation

Step-by-step explanation:

Given

tan a = $\frac{9}{40}$ = $\frac{opposite}{adjacent}$

We require the hypotenuse h

Using Pythagoras' identity

h² = 9² + 40² = 81 + 1600 = 1681 ( take square root of both sides )

h = $\sqrt{1681}$ = 41 , thus

sin a = $\frac{opposite}{hypotenuse}$ = $\frac{9}{41}$

cos a = $\frac{adjacent}{hypotenuse}$ = $\frac{40}{41}$

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2 years ago

A square tile has a side length of 12 cm. What is the area of the tile?

Lesechka [4]

Step-by-step explanation:

Area of square =side×side

=12×12

=144cm^2

Hope this helped! :)

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2 years ago

My life is helpless.... could you please help? i cant even understand this I'm only 10.

Nadya [2.5K]

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2 years ago