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Dvinal [7]
3 years ago
13

Models may change as new discoveries are made. Please select the best answer from the choices provided T F

Chemistry
1 answer:
Serjik [45]3 years ago
8 0
True.
For an example, look at the models of the atom. First, we have the plumb pudding model. Then that was replaced by the planetary model. That model was replaced by the quantum model. 
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31. Adding an additional oxygen atom to 02 creates....
cricket20 [7]
It creates chlorofluorocarbons(CFCs) also would create biooxygen but in the multiple choice it only shows the CFCs
4 0
3 years ago
Which statements accurately describe mass? Check all that apply.
Alexxandr [17]

Answer:

the second,third and last statement

Explanation:

please like and Mark as brainliest

4 0
3 years ago
Does an astronaut have more mass on earth then space? why or why not?
katovenus [111]

Answer:

No

Explanation:

No, his mass remains the same no matter where he is in the universe.

But then again the moon has less gravitational pull, therefore your weight and mass will be smaller in space and on the moon than on earth

I hope this was helpful! ;)

3 0
3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
belka [17]

Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

8 0
3 years ago
HELP FAST 100 PTSCalculate the amount of heat needed to convert 100.0 g of liquid water at 25 °C to water at 100 °C.
Alex Ar [27]

Answer:

31,380 Joules

Explanation:

Given Data:

Mass = m = 100 g

Temperature 1 = = 25 °C

Temperature 2 = = 100 °C

Specific Heat Constant = c = 4.184

Change in Temp. = ΔT = 100 - 25 = 75 °C

Required:

Heat = Q = ?

Formula:

Q = mcΔT

Solution:

Q = (100)(4.184)(75)

Q = 31, 380 Joules

Hope this helped!

~AH1807

4 0
3 years ago
Read 2 more answers
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