All categories

3 years ago

This what happen when climate changes

1 answer:

8 0

if you are talking about the climate change of today as in the heat your answer would be ,because the green house gases are trapping in the heat and reflecting it back down it disrupts the temperature everywhere. so the hot weather will become even HOTTER the cold weather will become warmer of come to late ,and the places such as Greenland and Antarctica which are covered in snow will start to melt making the whole globe more hot year by year

You might be interested in

In the relationship between ΔG and K for a given reaction, if ΔG is negative, what is K? K is equal to 0. K is equal to 1. K is

frutty [35]

K is greater than 1. #platolivesmatter

3 0

3 years ago

Read 2 more answers

What method is used to removed the unreacted copper (II) carbonate?

Evgen [1.6K]

Answer:

Filtration

Explanation:

Metal carbonate is insoluble, it is possible to filter off the unreacted substances leaving the desired salt solution

8 0

3 years ago

What would be the correct order of least(floats) to most(sinks) density?*

olya-2409 [2.1K]

Answer:

Explanation:

Water-Continental-Oceanic-Mantle

5 0

3 years ago

How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos

Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of $H_3PO_4$ = 54.219 g

Number of atoms of $Mg$ = $7.179\times 10^{23}$

Molar mass of $H_3PO_4$ = 98 g/mol

First we have to calculate the moles of $H_3PO_4$ and $Mg$ .

$\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}$

$\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol$

and,

$\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2$

From the balanced reaction we conclude that

As, 3 mole of $Mg$ react with 2 mole of $H_3PO_4$

So, 0.553 moles of $Mg$ react with $\frac{2}{3}\times 0.553=0.369$ moles of $H_3PO_4$

From this we conclude that, $H_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2$

From the reaction, we conclude that

As, 3 mole of $Mg$ react to give 3 mole of $H_2$

So, 0.553 mole of $Mg$ react to give 0.553 mole of $H_2$

Now we have to calculate the volume of $H_2$ gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies $0.553\times 22.4=12.4L$ volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0

3 years ago

What did sewage treatment in Ancient Rome and 19th century London have in common? How effective was this strategy and why?

anygoal [31]

Yea pretty much

Explanation:

4 0

3 years ago