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Shalnov [3]
3 years ago
10

I don’t understand how to solve this with the tables.

Mathematics
1 answer:
musickatia [10]3 years ago
6 0

Answer:

Table B and Graph B

Step-by-step explanation:

If you count how many spaces up the line in graph b goes up when it hits the next point, the y value increases by 4 every time, and the y value in table b is increasing by 4 every time.

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a shopkeeper buys cocacola 60 rupees a dozen and sell 6 rupees per bottle find his profit or loss persentage​
Lady_Fox [76]

Answer:

20%

Step-by-step explanation:

12 bottle is 60 rupees

each sold 6 ruppes

so 12 bottle cost 72 ruppes

12*100/60 = 20%

8 0
3 years ago
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What is the area of a circle with a radius of 1 foot?
vladimir2022 [97]

Pi feet squared (I hope I helped!)

5 0
3 years ago
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If two matrices, A and B, are equal, which of the
alexandr402 [8]

If A and B are equal:

Matrix A must be a diagonal matrix: FALSE.

We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:

A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]

Both matrices must be square: FALSE.

We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works

Both matrices must be the same size: TRUE

If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.

For any value of i, j; aij = bij: TRUE

Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.

8 0
3 years ago
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Angle 3 and angle 4 are supplementary angles. Angle 3 is 88. What is the measure of angle 4?
Mademuasel [1]
Since angles 3 and 4 are supplementary, they add up to 180 degrees.

Angle 3 is 88 degrees.

To get the measure of the last angle, let's subtract 88 from 180.

180 - 88 = 92

Thus, Angle 4 has a measure of 92 degrees.

Have an awesome day! :)
7 0
2 years ago
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. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
2 years ago
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