23 good luck hopefully you pass the test
Answer:
50 quarters and 28 nickels
Step-by-step solution:
We have two variables we are solving for. We will call them Q for the number of quarters and N for the number of nickels.
We know that the total number of coins is equal to 78, and we know that the total amount the coins are worth is equal to $13.90. With this information, we can set up a system of equations:
Q + N = 78
0.25Q + 0.05N = 13.90
Now we can solve for either Q or N in the first equation and solve by substitution by plugging the value into the second equation. Let's solve for Q:
Q = 78 - N
Now plug in 78-N for Q:
0.25(78-N) + 0.05N = 13.90
Distribute and combine like terms:
19.50 - 0.25N + 0.05N = 13.90
19.50 - 0.20N = 13.90
-0.20N = -5.60
N = 28
Now we know that there are 28 nickels. We can plug this into one of the original equations to solve for Q:
Q + 28 = 78
Q = 50
There are 50 quarters. We can verify our answer by plugging the values for A and N into the other equation (optional step to check work):
0.25(50) + 0.05(28) = 13.90
12.5 + 1.40 = 13.9
13.9 = 13.9
Our answer is correct.
Answer:
840 cm
Step-by-step explanation:
Given that in the question we have, : 9, 1 cm × 1 cm squares setting a 3 × 3 grid.
Therefore wire required in 3 x 3 grid is
3(3+1) + 3(3+1)
= 3 × 4 + 3 × 4
= 24 I'm
Similarly, the length of the wire required in 20 by 20 grid will be
=> 20(20+1) + 20(20+1)
=> 20 × 21 + 20 × 21
=> 420 + 420
= 840cm
Answer:
1) Radius of the cone = 9.5 cm
2) BA = 90.25 π cm²
3) SA = 384.7 π cm²
Step-by-step explanation:
1) Radius of the cone = 9.5 cm
2) Base Area of the cone =
BA = (π)(9.5)²
BA = 90.25 π cm²
3) Surface Area of Cone =
SA = π(9.5)(9.5 + √(29.5)²+(9.5)²)
SA = 9.5π(9.5 + 31)
SA = 9.5π(40.5)
SA = 384.7 π cm²
Edge 2022
