Answer:
5.25 times
Step-by-step explanation:
Beverage A and Beverage B are sold in identical cans.
From the above question
Beverage A is 4% sugar.
The portion of Beverage B that is sugar is 0.21.
Converting Portion of sugar in Beverage B to percentage we have :
0.21 × 100
= 21%
How many times more sugar is in Beverage B than Beverage A?
This is calculated as:
% Beverage B/% Beverage A
= 21%/4%
= 5.25
Hence Beverage B has 5.25 times more sugar than Beverage A.
Answer:
≈ 9.4 cm
Step-by-step explanation:
P(-4, -2), Q(4,3)
d= √(x2-x1)²+(y2-y1)²=√ (4+4)²+(3+2)²= √64+25 = √89 ≈ 9.4 cm
Answer:
25
Step-by-step explanation:
Answer:
-5
Step-by-step explanation: