Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
The probability that his number will be 4 is one in eleven, or 1/11.
This is how I would solve it, I would act as if there were 36 people in the class.
36÷6=6×5=30
30÷3=10×2=20
20/36=10/18=5/9
You could also try another number such as 24;
24×(5÷6)=20
20×(2/3)=13.3(3 repeating)
13.333/24=5/9
5/9 people have dogs.
Tell me if this helps.
Answer:
I think it is A and D but i'm sorry if i'm wrong
Step-by-step explanation:
Answer:
The slope of the line with points A(-2, -7) and B(3,5) is m = (12/5).
Step-by-step explanation:
The two pints are given as A(-2, -7) and B(3,5)
Slope of a line with points (a,b) and (c,d) is given as
So, here the slope of line AB is
or, m = 12/5
Hence, the slope of the line with points A(-2, -7) and B(3,5) is (12/5).
