Answer:
They have 425 candy bars ready to sell.
Step-by-step explanation:
Let,
x be the number of candy bars ready to sell
y be the number of chips ready to sell
According to given statement;
x+y=575 Eqn 1
x+0.5y= 500 Eqn 2
Subtracting Eqn 2 from Eqn 1
(x+y)-(x+0.5y)=575-500
x+y-x-0.5y=75
0.5y = 75
Dividing both sides by 0.5

Putting y=150 in Eqn 1
x+150 = 575
x = 575-150
x = 425
Hence,
They have 425 candy bars ready to sell.
Answer: the number must be placed in the box is 9
suppose: the number must be placed in the box is x
have:
5u + 3(4u - 6) = -3u -27 + 20u + x
⇔ 5u + 12u - 18 = -3u - 27 + 20u +x
⇔ 17u + 3u - 20u = -27 + 18 + x
⇔ 0 = x - 9
⇔ x = 9
Step-by-step explanation:
Greeting to you! My name is Cecille and I’m here to answer that question
For more explanation, please see the attachment
Answer:
False
Step-by-step explanation:
The totals of the rows and columns of a two way table are not called marginal distributions. They are called conditional distributions.
To write it in simplest form, you must find a common factor.
In

, 3 is a factor of both 3 and 9
3÷3=1 and 9÷3=3
So


is your answer in simplest form.