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3 years ago

A line with a slope of 1/2 passes through the point (2,-1). What is the equation of this line ?

2 answers:

4 0

Equation of a line tha passes through thte point (x1,y1) and has a lsope of m is
y-y1=m(x-x1)

given
m=1/2
point is (2,-1)
x1=2
y1=-1

y-(-1)=1/2(x-2)
y+1=1/2(x-2)
if yo want slope intercept
y+1=1/2x-1
y=(1/2)x-2

lora16 [44]3 years ago

3 0

I believe the equation would be y=mx+b, m being slope, b being y-intercept, so it would mean that you need to plug in the numbers. I believe the final equation would be y=1/2x+(-1)

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-377 = x - 1,000 i dont under stand it

Naddika [18.5K]

Answer:

$\boxed {x = 623}$

Step-by-step explanation:

Solve for the value of $x$ :

$-377 = x - 1,000$

-Switch sides:

$-377 = x - 1,000$

$x - 1,000 = -377$

-Add $1,000$ on both sides:

$x - 1,000 + 1,000 = -377 + 1,000$

$\boxed {x = 623}$

Therefore, the value of $x$ is $623$ .

4 0

3 years ago

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

3 years ago

A high school sewing club has 11 members. In how many different ways can they choose a president and vice president?

lorasvet [3.4K]

Since the order matters Person A and B can be chosen as AB (A pres B vice pres) or BA (B president A Vice president)

When the order matters we are talking about permutations. How many permutations of 11 taken 2 at a time are there.
It can be written like this 11nPr 2
It means start at 11 and multiply by the next lower number
11 x 10 = 110 ways they can choose.
Extension of the concept:
If there had been three positions President, Vice President, and Treasurer
then it would be 11nPr3 or 11 x 10 x 9
Once again the answer to your problem is 110.

6 0

3 years ago

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250 female nurses to 100 male nurses what is the ratio of male nurses to female nurses

BARSIC [14]

Answer:

2:5

it may be faster to google it

6 0

3 years ago

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Write how many hundreds, tens, and ones 118