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Verdich [7]
4 years ago
10

If f(x)=4x^2+1 and g(x) =x^2-5 find (f-g)(x)

Mathematics
1 answer:
docker41 [41]4 years ago
6 0

Answer:

\huge\boxed{(f-g)(x)=3x^2+6}

Step-by-step explanation:

(f-g)(x)=f(x)(x)\\\\\text{substitute}\ f(x)=4x^2+1\ \text{and}\ g(x)=x^2-5\\\\(f-g)(x)=(4x^2+1)-(x^2-5)=4x^2+1-x^2-(-5)=4x^2+1-x^2+5\\\\\text{combine like terms}\\\\(f-g)(x)=(4x^2-x^2)+(1+5)=3x^2+6

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Molodets [167]

Answer: x = -2 and y = 4


Step-by-step explanation:

We have given a system of equations

2x + 4y =12   ...........(1)

and

x + y = 2         .............(2)

Now to plot them in graph we need to find the points of the above linear equations .

From equation 1  ,we get

4y=12-2x\\\Rightarrow\ y=\frac{12-2x}{4}\\ \Rightarrow\ y=3-\frac{x}{2}\\\text{Put x=0, then} \\y=3-\frac{0}{2}=3\\\Rightarrow\ \text{Put x=6}\\y=3-\frac{6}{2} =3-3=0

So get the points (0,3) and (6,0).

From equation 2 ,we get

y=2-x\\\text{Put x=0}\\y=2-0=2\\\text{Put x=2}\\y=2-2=0

So we get the points (0,2) and (2,0).

So after plotting these points we get two lines intersecting at (-2,4).

Therefore our solution is x=-2 and y= 4.

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3 years ago
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mariarad [96]
I hope this helps you

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