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Nataliya [291]
3 years ago
15

Which of the following atoms:

Chemistry
1 answer:
lukranit [14]3 years ago
5 0
Mg, In, Pb,Co and Cs are all expected to form positive ions because they are considered types of metals. P, I, Cl, and O are going to form negative ions.
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Help with my math homework please (didn't mean to put chemistry)
alisha [4.7K]
Each of the terms of the sequence is a multiple of 4, starting with 4 x 1 = 4, so the rule for this sequence is 4n.
8 0
3 years ago
If 280.4 g of KOH react with an excess of FeCl3, how many grams of Fe(OH)3 will be produced?
aleksandrvk [35]

Answer:

From 00:11

Balance the Molecular Equation

From 01:35

Ions for the Complete Ionic Equation

From 03:04

Net Ionic EquationExplanation:

6 0
3 years ago
In what orbital would to valence electrons of strontium be found? a.) 5s b.) 4s c.) none d.) 5p​
KonstantinChe [14]

Answer:

The correct answer is 5s

Explanation:

Strontium atomic number = 38

Electronic configuration is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 5s^{2}

As $5s$ orbital is valence orbital in strontium, the outer electrons exists in that orbital only.

4 0
3 years ago
Consider the reaction.
Alekssandra [29.7K]

Answer:The correct answer is option C.

Explanation:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

At STP, 1 mol of gas occupies 22.4 L of volume

So, 100.0 L volume of NH_3will be occupied by :

\frac{1}{22.4 L}\times 100.0 L=4.4642 moles

According to reaction 2 moles NH_3 are obtained from 1 mole of N_2.

Then,4.4642 moles of NH_3 will be obtained from :

\frac{1}{2}\times 4.4642 that is 2.2321 moles of N_2

Mass of N_2 gas:

Moles of N_2 gas  Molar mass of N_2 gas:

2.2321 mol\times 28 g/mol=62.4988\approx 62.50 g

Hence, the correct answer is option C.

4 0
3 years ago
Read 2 more answers
g 8. A hydrogen atom is initially a rest and in the ground state. A proton with kinetic energy 1000 eV scatters off the atom. In
aleksley [76]

Answer:

Explanation:

Ionization energy of hydrogen atom is 13.6 eV . This energy will be provided by energetic proton , the kinetic energy of which is 1000 eV.  The kinetic energy of ionized electron is 15.2 eV . Kinetic energy of proton produced from from the ionization of hydrogen or the nucleus of the hydrogen atom is 4.3 eV . All these energy must have come from kinetic energy of initial proton.

So kinetic energy of projectile proton after collision

= 1000 - ( 13.6 + 15.2 + 4.3 ) eV.

= 966.9 eV .

8 0
3 years ago
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