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Alenkinab [10]
3 years ago
10

A liquid with a high surface tension exhibits __________.

Chemistry
2 answers:
sattari [20]3 years ago
5 0

Answer: strong cohesive forces

Explanation:

Surface tension is the net downward force acting on the surface of liquids due to the cohesive nature of liquids.

The force of attraction between similar molecules are called as cohesive forces and forces among different molecules are called as adhesive forces.

For example: Water molecules are bonded by strong hydrogen bonding between the hydrogen atom and the electronegative oxygen atom. Thus water molecules present on the surface are strongly attracted by the molecules present below the surface and thus act as a stretched membrane.  

The surface acquires a minimum surface are and thus acquire a spherical shape.

Thus the liquids with a high surface tension exhibits strong cohesive forces.

sergij07 [2.7K]3 years ago
4 0
Strong cohosive forces (A)
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4 years ago
The value for the equilibrium constant for the reaction 2SO2(g)+O2(g) rightleftharpoons 2SO3(g) is 4.0*10^ 1 24 at 298K What wou
MrRissso [65]

Answer:

The value for the equilibrium constant for the reaction 2SO2(g)+O2(g)  2SO3(g)     Kc=4.0*10^24\\ at 298K .

What would be the value for the equilibrium constant for the following reaction at the same temperature?

2SO3(g)  2SO2(g)+O2(g)

Explanation:

The Kc value for the reverse reaction of the first reaction that is:

2SO2(g)+O2(g)  2SO3(g)     Kc=4.0*10^{24}\\

Kc=\frac{SO3^{2} }{SO2^{2}.O2 }

For the reverse reaction,

2SO3(g)  2SO2(g)+O2(g)

Kc=\frac{SO2^{2}O2 }{SO3^{2}. }

So, it is the inverse of the first Kc value.

Hence, the new Kc value is:

Kc=\frac{1}{4.0*10^{24} } \\    =2.5*10^{-25}

Answer is :

Kc=2.5*10^-25.

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An iron ball is dropped onto a pavement from a height H. If half of the heat generated goes into warming the ball, find the temp
mr Goodwill [35]

The given question is incomplete. The complete question is as follows.

A 10 kg iron ball is dropped onto a pavement from a height of 100 m. If half of the heat generated goes into warming the ball,find the temperature increase of the ball. (In Sl units, the specific heat capacity of iron is 450 J/kg.C degree).

Explanation:

In the given case, when the ball comes in contact with the pavement then its kinetic energy will be equal to potential energy of the ball before it was dropped. Half the K.E heats the ball.

As K.E = P.E = mgh

So, mgh = 10 \times 10 \times 100 = 10,000 joules

And, half of this is 5,000 joules

As we know that

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\Delta T = \frac{5000}{4500}

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          \frac{mgh}{2} = m \times C \times \Delta T

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As, the result is independent of mass which is why the result is the same for any ball of any mass.

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4 years ago
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