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Triss [41]
3 years ago
6

Which of these is not an example of a physical change?

Physics
2 answers:
horsena [70]3 years ago
5 0
A. a nail rusting is not a physical change its a chemical change
amm18123 years ago
3 0
A nail rusting is an example of chemical change as the iron is oxidized to become rust. This is not a physical change.
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Can we have the Doppler effect with light waves? How?
Mekhanik [1.2K]

Answer:

Besides sound and radio waves, the Doppler effect also affects the light emitted by other bodies in space. If a body in space is "blue shifted," its light waves are compacted and it is coming towards us. If it is "red shifted" the light waves are spread apart, and it is traveling away from us.

Explanation:

7 0
3 years ago
How many atoms are in a molecule of C6H12O6?
Andrews [41]

Answer:

The answer is 24

Explanation:

Its made up of 6 carbon atoms

6 oxygen atoms

12 hydrogen atoms

5 0
3 years ago
a plane passes over Point A with a velocity of 8,000 m/s north. Forty seconds later it passes over Point B with a velocity of 10
ValentinkaMS [17]

Acceleration = (change in velocity) / (time for the change)

Change in velocity = (ending velocity) - (starting velocity)

Change in the plane's velocity = (10,000 m/s north) - (8,000 m/s north)

Change in the plane's velocity = 2,000 m/s north

Time for the change = 40 seconds

Acceleration = (2,000 m/s north) / (40 seconds)

<em>Acceleration = 50 m/s² north </em>

8 0
3 years ago
If 27 J of work are needed to stretch a spring from 15 cm to 21 cm and 45 J are needed to stretch it from 21 cm to 27 cm, what i
kupik [55]

Answer:

9 cm.

Explanation:

The energy used for stretch the spring from 15 cm to 21 cm will be , E_{1}=27J

The energy used for stretch the spring from 21 cm to 27 cm will be , E_{2}=45J

using the energy of spring formula ,we find that

27 = \frac{1}{2}K((21-L^{2})-(15-L^{2}))

45 = \frac{1}{2}K((27-L^{2})-(21-L^{2}))

Dividing both the equation will get,

\frac{3}{5}=\frac{(21-L)^{2}-(15-L)^{2}}{(27-L)^{2}-(21-L)^{2}}\\5((21-L)^{2}-(15-L)^{2})=3((27-L)^{2}-(21-L)^{2})\\3(729 - 54L + L^{2}- 441 + 42L - L^{2} ) = 5(441 - 42L + L^{2} - 225 + 30L - L^{2} )\\3(288 - 12L) = 5(216 - 12L)\\24L = 216\\L = 9 cm

Therefore, the natural length of the spring is, 9 cm.

4 0
3 years ago
Calculate the broadcast wavelength of the radio station 99.90 fm. seconds
taurus [48]

The radio waves are electromagnetic wave, so it travels with velocity of light i.e 3\times 10^{8} \ m/s.

We can use the relation between frequency, wavelength and speed as

\lambda =\frac{c}{f}

Here c is speed of light, \lambda is wavelength and f is frequency and its value is given 99.90 FM, it is actually in megahertz  (i.e 99.90 MHz).

Therefore,

\lambda =\frac{3 \times 10^{8}\ m/s }{99.90 \times 10^{6} \ Hz} = 3.003 \ m.

Thus, the broadcast wavelength of the given radio station is 3.003 m.

8 0
4 years ago
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