Question

A cube of wood having an edge dimension of 20.0cm and a density of 650 kg /m³ floats on water. (a) What is the distance from the horizontal top surface of the cube to the water level?

Answer 1

The distance from the horizontal top surface of the cube to the water level is "6.282 cm".

What is Archimedes' principle?

According to Archimedes' principle, the weight of the fluid that the body displaces is equal to the upward buoyant force that is applied to a body submerged in a fluid, whether fully or partially. The Archimedes' principle is a fundamental physical law in fluid mechanics. It was created by Syracuse's Archimedes.

According to Archimedes' principle, a body submerged in a fluid experiences an upward force proportional to the weight of the fluid that has been displaced. One of the prerequisites for equilibrium is this. We believe that the buoyancy force, also known as the centre of buoyancy, is situated in the middle of the submerged hull.

From Archimedes' principle, we get

$\rightarrow L^3 \rho_{\text {Wood }} &=L^2 d \rho_{\text {Water }}$

$d &=L \frac{\rho_{\text {Waat }}}{\rho_{\text {Water }}}$

$&=18 \times \frac{651}{1000}$

=11.72cm

So,

The distance from horizontal top to the water level will be:

=18-11.72

=6.282cm

To learn more about Archimedes' principle refer to:

brainly.com/question/1155674

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