Answer:
35.3 N
Explanation:
U = 0, V = 0.61 m/s, s = 0.39 m
Let a be the acceleration.
Use third equation of motion
V^2 = u^2 + 2 as
0.61 × 0.61 = 0 + 2 × a × 0.39
a = 0.477 m/s^2
Force = mass × acceleration
F = 74 × 0.477 = 35.3 N
<span>A particle released during the fission of uranium-235 is a "Neutron"</span>
The atoms furthest from the nucleus
The centripetal force on the car as it goes around the second curve is twice that compared to the first.
What is Centripetal force?
It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.
The formula of Centripetal force is:
F(c) = (m* v^2) / r
Here,
At the first curve,
The curve of radius = r
The constant speed = v
At the second curve,
The car speed (v')= 2 v
The radius of the curve (r')=2 r
According to the formula of centripetal Force:
As the car goes around the second curve,
F'(c) = m*v'^2 / r'
F'(c) = m* (2*v)^2 / 2r
F'(c) = 2* F
Thus,
The centripetal force on the car as it goes around the second curve is twice that compared to the first.
Learn more about centripetal force here:
<u>brainly.com/question/14317060</u>
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Answer:
A. 
B. t = 50 s
Explanation:
A. The vectorial equation of the person who is getting closer to the other person is:
r: position vector
v: speed vector = 6m/s i (if you consider the motion as a horizontal motion)
Then, you replace and obtain:
B. The time is:
d: distance to the observer = 300m
v: speed of the person on the car = 6.00 m/s
