The lawnmower accelerates in the positive horizontal direction, so that the net horizontal force is, by Newton's second law,
(70 N) cos(-50°) = <em>m</em> (1.8 m/s²)
where <em>m</em> is the mass of the lawnmower. Solve for <em>m</em> :
<em>m</em> = ((70 N) cos(-50°)) / (1.8 m/s²)
<em>m</em> ≈ 25 kg
The lawnmower presumably doesn't get lifted off the ground, so that the net vertical force is 0. If <em>n</em> is the magnitude of the normal force, then by Newton's second law,
<em>n</em> - <em>m g</em> + (70 N) sin(-50°) = 0
<em>n</em> = <em>m g</em> + (70 N) sin(50°)
<em>n</em> = (25 kg) (9.8 m/s²) + (70 N) sin(50°)
<em>n</em> ≈ 300 N
The Coulomb force is equal to the constant k times the product of charge one and charge two over radius.
F=k((q1q2)/r)
Im really sorry. pls dont report this comment. i need points. I have a question but I am bad at english and I cant answer peoples
Answer: C. Be more dense and flow under warm air.
Explanation:
think of a supermarket selling dairy products and when you open the fridge to get the milk, outside the supermarket is hot and inside the fridge is cold ice.
