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Ulleksa [173]
3 years ago
12

Wave-particle duality tells us that wave and particle models apply to all objects whatever the size, so why don't we observe wav

e properties in macroscopic objects?
Physics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

Because the wavelengths of macroscopic objects are too short for them to be detectable.

Explanation:

Wavelength of an object is given by de Broglie wavelength as:

\lambda=\frac{h}{mv}

Where, 'h' is Planck's constant, 'm' is mass of object and 'v' is its velocity.

So, for macroscopic objects, the mass is very large compared to microscopic objects. As we can observe from the above formula, there is an inverse relationship between the mass and wavelength of the object.

So, for vary larger masses, the wavelength would be too short and one will find it undetectable. Therefore, we don't observe wave properties in macroscopic objects.

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You accidentally slide a glass of iced tea off a table that is 0.75 m tall. How
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Answer:

B

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s=  \frac{1}{2} gt ^{2}

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A disk has a radius of 30 cm and a mass of 0.3 kg and is turning at 3.0 rev/s. A trickle of sand falls onto the disk at a distan
Pani-rosa [81]

Answer:

The mass of the sand that will fall on the disk to decrease the is 0.3375 kg

Explanation:

Moment before = Moment after

I \omega_i = I \omega_f +mr^2 \omega_f\\\\mr^2 \omega_f = I \omega_i  - I \omega_f \\\\m = \frac{ I \omega_i  - I \omega_f}{r^2 \omega_f }

where;

I is moment of inertia = Mr² = 0.3 x (0.3)² = 0.027 kg.m²

substitute this in the above equation;

m = \frac{ 0.027[3(2 \pi)  - 2(2 \pi)]} {0.2^2 * 6\pi } = \frac{ 0.027[6 \pi  - 4\pi]} {0.2^2 * 4\pi }\\\\m = 0.3375kg

Therefore, the mass of the sand that will fall on the disk to decrease the is 0.3375 kg

7 0
3 years ago
When electrons are accelerated by 2450v in an electron microscope they will have wavelengths of
Sholpan [36]
I think the answer is A I’m
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2 years ago
5. A sled with no initial velocity accelerates at a rate of 5.0 m/s2 down a hill. How
ad-work [718]

Answer:

60 m/s

Explanation:

a =  \frac{vf - vi}{t}

5.0 =  \frac{vf - 0}{12}

5.0 \times 12 = vf

60 = vf

6 0
3 years ago
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