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Ulleksa [173]
3 years ago
12

Wave-particle duality tells us that wave and particle models apply to all objects whatever the size, so why don't we observe wav

e properties in macroscopic objects?
Physics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

Because the wavelengths of macroscopic objects are too short for them to be detectable.

Explanation:

Wavelength of an object is given by de Broglie wavelength as:

\lambda=\frac{h}{mv}

Where, 'h' is Planck's constant, 'm' is mass of object and 'v' is its velocity.

So, for macroscopic objects, the mass is very large compared to microscopic objects. As we can observe from the above formula, there is an inverse relationship between the mass and wavelength of the object.

So, for vary larger masses, the wavelength would be too short and one will find it undetectable. Therefore, we don't observe wave properties in macroscopic objects.

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A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, F_f, acting in the opposite direction (backward)

So the net force acting on the box is

F_{net}=F-F_f

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

F_{net}=ma

And so

F-F_f = ma

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

a=0

Therefore we have:

F-F_f=0

Which means

F_f=F

And since we are told that

F=25 N

This means that the force of friction is also 25 N:

F_f=F=25 N

6 0
4 years ago
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Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. one force is 9.0 n, acting due east, an
Zolol [24]
The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
 We have then:
 Horizontal = 9-9.2cos (58) = 4.124742769 N.
 Vertical = 9.2sin (58) = 7.802042485 N
 Then, the resulting net force is:
 F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
 Then by definition:
 F = m * a
 Clearing the acceleration:
 a = F / m
 a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
 answer:
 The magnitude of the body's acceleration is
 2.941756275 m / s ^ 2
6 0
3 years ago
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