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Ulleksa [173]
3 years ago
12

Wave-particle duality tells us that wave and particle models apply to all objects whatever the size, so why don't we observe wav

e properties in macroscopic objects?
Physics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

Because the wavelengths of macroscopic objects are too short for them to be detectable.

Explanation:

Wavelength of an object is given by de Broglie wavelength as:

\lambda=\frac{h}{mv}

Where, 'h' is Planck's constant, 'm' is mass of object and 'v' is its velocity.

So, for macroscopic objects, the mass is very large compared to microscopic objects. As we can observe from the above formula, there is an inverse relationship between the mass and wavelength of the object.

So, for vary larger masses, the wavelength would be too short and one will find it undetectable. Therefore, we don't observe wave properties in macroscopic objects.

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A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i
Lubov Fominskaja [6]

Answer:

11.8 m/s

Explanation:

At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).

Sum of forces in the centripetal direction:

∑F = ma

mg − N = m v²/r

At the maximum speed, the normal force is 0.

mg = m v²/r

g = v²/r

v = √(gr)

v = √(9.8 m/s² × 14.2 m)

v = 11.8 m/s

3 0
3 years ago
A wheel of radius 30 cm is rotating at a rate of 2.0 revolutions every 0.080 s. (A) through what angle, in radians, does the whe
Alchen [17]
A)
2revs in 0.08s
   so in 1s thats 25revs
therefore thats <u>50π radians</u> in one second

b)
well, ω=2π/T
therefore ω=50π = 157.079rads^-1
and v=rω where r is in meters;
v=0.3x157.079
<u>v=47.123ms^-1</u>

c)
f=1/T
f=1/period for one rotation
1 rotation = 0.08/2 = 0.04
f=1/0.04
<u>f=25Hz</u>

6 0
3 years ago
Convert:<br> 1) 2kg into gram<br> 2) 5200m into km<br> 3) 20cm into m
aivan3 [116]
1) 2 kilograms converted into grams is 2000

2) 5200 meters converted into kilometers is 5.2

3) 20 centimeters converted into meters is 0.2
8 0
3 years ago
The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8. What is the ideal efficiency of the engine? Use
vodomira [7]

Answer:

e=58%

Explanation:

Given data

The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8.

Solution

We want to calculate the ideal efficiency of the engine when ratio of heat capacity for gas used  γ=1.40. Ideal efficiency (e) of the Otto cycle given by:

e=1-(\frac{1}{r^{Y-1} } )\\

Substitute the given values to find efficiency e

e=1-\frac{1}{8.8^{1.4-1} } \\e=0.58\\

e=58%

8 0
3 years ago
2kg of water at 30 C is poured into a 1kg copper beaker at 20 C.
GREYUIT [131]

The temperature of the water and copper beaker be together is 29.6⁰C.

<h3>What is the equilibrium temperature of both substance?</h3>

The final temperature or equilibrium temperature of the water and copper beaker is calculated by applying the principle of conservation of energy.

Heat lost by the water = Heat gained by the copper beaker

mcΔθ (water) = mcΔθ (copper)

where;

  • m is mass
  • c is specific heat capacity
  • Δθ is change in temperature

m₁c₁(T₁ - T) = m₂c₂(T - T₂)

where;

  • T₁ is the initial temperature of water
  • T₂ is the initial temperature of copper beaker
  • T is the equilibrium temperature

Specific heat capacity of copper, c₂ = 389 J/kgK

Specific heat capacity of water , c₁ = 4200 J/kgK

(2)(4200)(30 - T) = (1)(389)(T - 20)

252,000 - 8400T = 389T - 7780

259,780 = 8789T

T = 259,780 /8789

T = 29.6⁰C

Learn more about equilibrium temperature here: brainly.com/question/8925446

#SPJ1

8 0
2 years ago
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