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4 years ago

1 mole solution of NaCl contains

Chemistry

1 answer:

Mamont248 [21]4 years ago

7 0

Answer:

If you dissolve 58.44g of NaCl in a final volume of 1 liter, you have made a 1M NaCl solution, a 1 molar solution.

Explanation:

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Assume that the total volume of a metal sample is the sum of the volume occupied by the metal ions making up the lattice and the

mojhsa [17]

Answer:

92.4%

Explanation:

The volume per cubic meter of sodium preoccupy by the sodium ions is

$V_{Na} = n \times V$

where;

volume (V) of each Na atom = $\dfrac{ 4}{3} \pi r^3$

Radius of each ion = 97.3 pm = 97.3 × 10⁻¹²

no.of atoms in the sample n = mass of the sample / ( molar mass / NA)

mass of the sample per cubic metre = 911 kg/m³

∴

$V = \bigg [ \dfrac{4}{3} \pi r^3 \bigg ] \bigg [\dfrac{MN_A}{m} \bigg ]$

$V = \bigg [ \dfrac{4}{3} \pi (97.3 \times 10^{-12} )^3 \bigg ] \bigg [\dfrac{ (911 kg/m^3 (m^3))(6.023\times 10^{23})}{27.7 \times10^{-3}\ kg/mol } \bigg ]$

V = 0.07643 m³

The fraction of available conduction electrons are;

= (1 - V)

= 1 - 0.07643

= 0.92357

≅ 92.4%

5 0

3 years ago

Magnesium has two electrons in its outer shell and chlorine has seven electrons in its outer shell how are the electrons transfe

HACTEHA [7]

Thru ionic bonding. The oppositely charged ions attract each other so ionic bond forms. Ionic bonding occurs when a metal bonds with a non-metal.

5 0

3 years ago

What is the molarity of solution containing 1.5 mol NaOH and 0.25 kg of water?

sladkih [1.3K]

Answer:

Molarity= 6M

Explanation:

Volume= 0.25L

Applying

n= CV

1.5= C×0.25

C= 6M

8 0

3 years ago

Oxygen gas is generated in the laboratory by the thermal decomposition of potassium chlorate what volume of oxygen is generated

Kruka [31]

The answer is 2 potassium

8 0

3 years ago

A. In the complete reaction of 22.99 g of sodium

fenix001 [56]

Answer : 58.44 g

<h3>Further explanation</h3>

The reaction

$\tt Na+Cl\Rightarrow NaCl$

mole ratio :

Na : Cl : NaCl = 1 : 1 : 1

Molar mass of Na : 22,989769 g/mol = 22.99 g/mol

Molar mass of Cl : 35,453 g/mol= 35.45 g/mol

Molar mass of NaCl : 58,44 g/mol

Let's check the mol for reactant (Na and Cl) and product(NaCl)

mol of Na :

$\tt mol=\dfrac{22.99}{22.99}=1$

mol of Cl :

$\tt mol=\dfrac{35.45}{35.45}=1$

Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1

so that the mole of the product can be determined from the mol Na or Cl, which is 1

mass of NaCl :

$\tt =\dfrac{mol~NaCl}{mol~Na}\times MW~NaCl\\\\=\dfrac{1}{1}\times 58.44\\\\=\boxed{\bold{58.44~g}}$

3 0

4 years ago