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JulsSmile [24]
3 years ago
12

1 mole solution of NaCl contains

Chemistry
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

If you dissolve 58.44g of NaCl in a final volume of 1 liter, you have made a 1M NaCl solution, a 1 molar solution.

Explanation:

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For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →
Vinvika [58]

Answer : The oxidizing element is N and reducing element is O. 

KNO_{3} is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

KNO_{3} \rightarrow KNO_{2} +O_{2}

KNO_{3}  act as an oxidizing agent.

The oxidation number of N in KNO_{3} is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in KNO_{2}  is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number  reduced this means KNO_{3} itself get reduced to KNO_{2} and it can act as an oxidizing agent.

KNO_{3}  act as a reducing agent.

KNO_{3} \rightarrow KNO_{2} +O_{2}

The oxidation number of O in KNO_{3} is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in O_{2} is Zero (o).

Now, we conclude that the oxidation number increases this means KNO_{3} itself get oxidized to O_{2} and it can act as reducing agent.





                     

4 0
3 years ago
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