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PtichkaEL [24]
3 years ago
12

Write formulas and names for two binary molecular compounds

Chemistry
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

NaCl sodium chloride

HF hydrogen flouride

Explanation:

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Please help me with this or I may get an F in chemistry :(
umka21 [38]

Answer:

Subconscious - psychic activity just below the level of awareness

Election - the act of electing someone

Explanation:

I hope this helped enough, good luck in chemistry!

8 0
3 years ago
3 natural chemicals a part of our life
Mademuasel [1]
Sodium chloride, methane gas and water
4 0
3 years ago
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Compared to other stars we observe, the Sun appears bigger and brighter because:
Kipish [7]

Answer:

Compared to other stars we observe, the Sun appears bigger and brighter because it is much closer to earth.

Objects closer to earth appear to be much bigger and brighter.

Let me know if this helps!

3 0
2 years ago
Read 2 more answers
Subject: Chemistry<br><br><br>whoever does this right will give the brainliest &lt;3)
Andru [333]

Answer:

1 A

3 main types of bond are

Ionic bond ( formed due to complete transfer of electron between atoms(

Covalent bond ( formed by mutual sharing of electron)

Metalic bond ( present in the metals due to mobile electrons)

1 B bond in CaO is ionic bond formation in attached image

1 C hydrogen bond with nitrogen is covelent NH3 ammonia is formed because a bond between two non metals is expected to be covalent

More their electronegativity difference between hydrogen and nitrogen is less than 1.7 that makes it covalent

Explanation:

4 0
2 years ago
Read 2 more answers
When 1.95 g of co(no3)2 is dissolved in 0.350 l of 0.220 m koh, what are [ co2+], [ co(oh)42−], and [ oh−] if kf of co(oh)42− =
Airida [17]
Mass of Co(NO₃)₂ = 1.95 g
V KOH = 0.350 L
[KOH] = 0.220 M
Kf = 5.0 x 10⁹
molar mass of Co(NO₃)₂ = 182.943 g/mol
so [Co(NO₃)₂] = 1.95 / (0.350 * 182.943) = 0.03045 M
[Co²⁺] = 0.03045 M
[OH⁻] = 0.22 M
chemical reaction:
             Co²⁺(aq) + 4 OH⁻    ⇄      Co(OH)₄²⁻
I (M)      0.03045      0.22                   0
C (M)   - 0.03045   - 4 (0.03045)      0.03045
E (M)       - x         0.22 - 4(0.03045)   0.03045
                              = 0.0982
Kf  = [Co(OH)₄²⁻] / [Co⁺²][OH⁻]⁴
5.0 x 10⁹ = (0.03045) / x (0.0982)⁴
x = 6.5489 x 10⁻⁸
at equilibrium:
[Co²⁺] = 6.54 x 10⁻⁸
[OH⁻] = 0.0982 M
[Co(OH)₄²⁻] = 0.03045 M



4 0
3 years ago
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