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3 years ago

A closed flask contains gas at STP. If the temperature is raised to 400 K what will the pressure be in atm?

Chemistry

1 answer:

balandron [24]3 years ago

5 0

Answer:

The answer is 1.5 atm

Explanation:

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Can anybody do this?

lukranit [14]

Answer:

0.17907

Explanation:

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3 years ago

The pressure system begins at 99.7 kpa.the volume of the gas is 150ml . What would be the final volume in the system if the pres

____ [38]

Assuming ideal behavior of the gas for a fixed amount when temperature is held constant, the pressure and volume are inversely proportional as given by the expression
P1V1 = P2V2
where the terms with subscripts of one represent the initial conditions for pressure and volume of the gas while for terms with subscripts of two represent the final conditions.
Rearranging the Boyle's law equation to calculate for the final volume V2:
V2 = P1V1 / P2
V2 = (99.7 kPa)(150 mL) / 99.8 kPa
V2 = 149.85 mL

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3 years ago

4. Nowadays, clinical thermometer is replaced by digital thermometer,why?<br>

White raven [17]

Answer:

<h2>Digital thermometer are used these days instead of clinical thermometers because: Digital thermometers are designed to be more accurate. Most digital thermometers have digital screening which extract temperature of wherever you are measuring. </h2>

4 0

3 years ago

What type of ion does neutral produces

Yuki888 [10]

Answer:

Neutral ions

Explanation:

Because they have a neutral charge They can only produce neutrally.

4 0

3 years ago

(CH3)2-CH-CH2-O(CH3)3IUPAC NAME

bazaltina [42]

Answer:

1-(tert-butoxy)-2-methylpropane

Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.

Explanation:

<em>Structural formula is attached</em>

IUPAC naming rules

1. start numbering the chain from the functional group. In this compound we start from oxygen side.

2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.

3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.

4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane

5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane

3 0

4 years ago