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Maru [420]
2 years ago
9

I need help with this please

Chemistry
1 answer:
Airida [17]2 years ago
3 0

Answer:

really?!

Explanation:

this is a test your suppose to answer it

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What is the maximum mass of ethyl alcohol you could boil with 1000 j of heat, starting from 22 ∘c?
kramer

solution:

1000 = m*2400*(78-22) + m*8.79*10^5

1000= 134400m + 879000m

1000= 1030200m

m = 1000/1013400

m= 1013.4 grams

the final answer is 0.9706 grams


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3 years ago
How many Dalmatian puppies are in Pongo and Perdita’s litter?
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3 years ago
Calcium is an element. What is the smallest particle of calcium that has the same chemical properties of calcium?
Verdich [7]

Answer:

A. An Atom

Explanation:

An atom is the smallest particle of an element, having the same chemical properties as the bulk element.

5 0
2 years ago
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8. What volume (ml) of a 5.45 M lead nitrate solution must be diluted to 820.7 ml to make a
Ganezh [65]

212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.

Answer:

Option A.

Explanation:

Similar to Avagadro's law, there is another law termed as dilution law. As the product of volume and normality of the reactant is equal to the product of volume and normality of the product from the Avagadro's law. In dilution law, it will be as product of volume and concentration of the solute of the reactant is equal to the product of volume and concentration of solution.

C_{1} V_{1} =C_{2} V_{2}

So, as per the given question C1 = 5.45 M of lead nitrate and V1 has to be found. While C2 is 1.41 M of lead nitrate and V2 is 820.7 ml.

Then, (5.45*V_{1} ) = (820.7*1.41)

V_{1}=\frac{820.7*1.41}{5.45}=  212.33 ml

So nearly 212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.

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3 years ago
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