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kolezko [41]
3 years ago
9

License plates are made using 2 letters followed by 3 digits. How many plates can be made if repetition of letters and digits is

allowed?
Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0
Answer:
number of possible combinations = 676000

Explanation:
We have:
26 possible letters (a to z)
10 possible digits(0 to 9)
2 letters followed by 3 digits

For letters, since repetition is allowed, therefore, each of the two letters can be any of the possible 26 alphabetical letters (a to z)
For digits, since repetition is allowed, therefore, each digit of the three can be any of the possible 10 digits (0 to 9)

Therefore:
number of combinations = letter * letter * digit * digit * digit
number of combinations = 26 * 26 * 10 * 10 * 10
number of possible combinations = 676000

Hope this helps :)
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Dayren is driving ti visit family. She drives at an average of 65 miles per hour. She drives 227.5 miles before lunch and then 9
lianna [129]

Answer:

5 hours

Step-by-step explanation:

227.5+97.5=325

325/65=5

3 0
3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
FIND THE SUM:<br> (6x^2-2x-3)+(x^2-3x+1)<br><br> 1.6x^2+6x+3<br> 2.7x^2+5x+2<br> 3.7x^2-5x-2
Butoxors [25]

8x^2-5x-2

method

open bracket

6x^2-2x-3+x^2-3x+1

collect like terms

6x^2+2x^2-3-3x+1

8x^2-3-3x+1

again collect like terms

8x^2-2x-3x-3+1

8x^2-5x-3+1. (-×-=+ addition but keeping sign minus

8x-5x-2. (-×+=-)

5 0
2 years ago
Mike discovered that the pool in his backyard is leaking slowly. The pool holds 17,897 gallons of water, and is leaking at a rat
pishuonlain [190]

Answer:

Gallons of water remaining = 16,962 gallons

Step-by-step explanation:

Total capacity of the pool = 17,897 gallons

Rate of leakage per day = 5 gallons

Number of days = 187 days

how many gallons of water will remain in the pool after 187 days?

Gallons of water remaining = Total capacity of the pool - (Rate of leakage per day × Number of days

= 17,897 - (5 × 187)

= 17,897 - 935

= 16,962 gallons

Gallons of water remaining = 16,962 gallons

8 0
2 years ago
I need help on this. I've no idea about this. Please help me...​
Mashcka [7]

Answer:

Answers are below.

Step-by-step explanation:

Hope this helps:)

4 0
2 years ago
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