Answer:
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Explanation:
Fusion creates less radioactive material and has nearly an unlimited fuel supply. Fusion also makes several times more energy than fission.
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Answer:
See explanation
Explanation:
One of the ways of driving a reaction towards the forward direction is the removal of one of the products. This will shift the equilibrum towards the right hand side.
Hence, by distilling one of the products from the system, the equilibrum was shifted towards the right hand side and a high percentage of product is obtained.
Answer : The equilibrium concentration of
will be, (C) ![2.82\times 10^{-1}](https://tex.z-dn.net/?f=2.82%5Ctimes%2010%5E%7B-1%7D)
Explanation : Given,
Equilibrium constant = 14.5
Concentration of
at equilibrium = 0.15 M
Concentration of
at equilibrium = 0.36 M
The balanced equilibrium reaction is,
![CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)](https://tex.z-dn.net/?f=CO%28g%29%2B2H_2%28g%29%5Crightleftharpoons%20CH_3OH%28g%29)
The expression of equilibrium constant for the reaction will be:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
Now put all the values in this expression, we get:
![14.5=\frac{[CH_3OH]}{(0.15)\times (0.36)^2}](https://tex.z-dn.net/?f=14.5%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%280.15%29%5Ctimes%20%280.36%29%5E2%7D)
![[CH_3OH]=2.82\times 10^{-1}M](https://tex.z-dn.net/?f=%5BCH_3OH%5D%3D2.82%5Ctimes%2010%5E%7B-1%7DM)
Therefore, the equilibrium concentration of
will be, (C) ![2.82\times 10^{-1}](https://tex.z-dn.net/?f=2.82%5Ctimes%2010%5E%7B-1%7D)