Answer:
128 g of Li will react with 86.1 g of N₂ to completely consume it.
Solution:
The balance chemical equation is as follow,
<span> 6 Li + N</span>₂ → 2 Li₃<span>N
According to this equation,
28 g (1 mole) N</span>₂ reacts with = 41.64 g (6 moles) of Li
So,
86.1 g of N₂ will react with = X g of Li
Solving for X,
X = (86.1 g × 41.64 g) ÷ 28 g
X = 128 g of Li
Answer:
a delayed neutron is a neutron emitted after a nuclear fission event, by one of the fission products (or actually, a fission product daughter after beta decay), any time from a few milliseconds to a few minutes after the fission event.
Explanation:
The answer is "thermal energy."
Answer:
B.
Explanation:
Na is Sodium and Cl is Chlorine [Chloride]
Answer:
Explanation:
To calculate [H⁺] first we <u>calculate the total number of H⁺ ions</u>.
H⁺ from HCl ⇒ 49.3 mL * 1.19 gSolution/mL * 38 gHCl / 100 gSolution = 22.29 g HCl
- 22.29 g HCl ÷ 36.45 g/mol = 0.612 mol HCl = 0.612 mol H⁺
H⁺ from HNO₃ ⇒ 19.5 mL * 1.42 gSolution/mL * 70 gHCl / 100 gSolution = 19.38 g HNO₃
- 19.38 g HNO₃ ÷ 63 g/mol = 0.308 mol HNO₃ = 0.308 mol H⁺
Total H⁺ moles = 0.612 + 0.308 = 0.920 mol H⁺
Final Volume = 1.00 L
- [H⁺] = 0.920 mol / 1.0 L = 0.920 M
Now we<u> calculate pH</u>:
<u>To calculate [OH⁻], we calculate pOH</u>:
- pOH = 14 - 0.036 = 13.964
pOH = 13.964 = -log[OH⁻]
- = [OH⁻] = 1.086x10⁻¹⁴ M