Answer:
Explanation:
You can deal with this question using two different but related approachs.
1) <u>First approach: 1 mole of gas at 1 atm and 0°C occupy 22.4 liter</u>.
With that you can set a proportion:
- 1 mole / 22.4 liter = 2.00 / V
⇒ V = 2.00 mole × 22.4 liter / 1 mole = 44.8 liter.
<u>2) Second approach: use ideal gas equation:</u>
⇒ V = nRT / p
- V = 2.00 moles × 0.0821 atm-liter / K-mol × 273.15 K / 1 atm = 44.85 liter ≈ 44.9 liter.
There, the two calculations yield the same result, although the second one is more accurate only if you need to use 3 or more significant digits, which is not correct in this case.
If you measure the presure as 1.0 atm (two significant digits) and the temperature as 0.0 °C (two significant digits), the volume must be resported with two significant digits, which yileds to the same result with both calculations: 45 liter.
Answer: E
Hope this helped :)
It is 10 times larger. 1 centigram = 10 miligrams, which means that it is 10 times larger.
Probably the most important is electronegativity. That’s sort of the force that compels electrons to transfer to other atoms, or favor specific atoms in covalent bonds.
The amount of valence electrons is also key, I think.
Are there some options? A word bank? Mult choice?