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algol13
3 years ago
11

If a frog initially contained 2 grams of carbon-14 and the half-life of carbon-14 is 5,730 years, how much carbon-14 remains in

the frog after 5,730 years?
Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
5 0
Half life is the time taken for a radioactive isotope to decay by half its original mass. In this case the half life of carbon-14 is 5.730 years. 
Using the formula;
New mass = original mass × (1/2)^n; where n is the number of half lives (in this case n=1 ) 
New mass = 2 g × (1/2)^1     
                  = 1 g
Therefore; the mass of carbon-14 that remains will be 1 g 
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Answer:

The dosage of the solution is 2.5 parts per million.

Explanation:

The solvent proportion in parts per million is equal to the ratio of solution in miligrams to ratio of water in miligrams multiplied by a million. (A kilogram is equivalent to a million miligrams) That is:

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3 0
3 years ago
How many atoms are there in 1 g of argon?
amm1812

Answer:

1.5057×10^22 atom

Explanation:

As we

1 mole of argon = 40 g of argon

i.e 40 g of argon = 1 mole of argon

1 g of argon = 1/40 mole of argon

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1/40 mole if argon = 1/40 ×6.023×10^23

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2 years ago
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AlexFokin [52]
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2) When n and V are constant:


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3) when n and p are constant


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7 0
3 years ago
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