If a frog initially contained 2 grams of carbon-14 and the half-life of carbon-14 is 5,730 years, how much carbon-14 remains in
1 answer:
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Explanation:
The given reaction is as follows.
Initial : 0.160 0.160 0
Change : -x -x 2x
Equilibrium: 0.160 - x 0.160 - x x
It is given that = [0.160 - x] = 0.036 M
and, = [0.160 - x] = 0.036 M
so, x = (0.160 - 0.036) M
= 0.124 M
As, [HI] = 2x.
So, [HI] =
= 0.248 M
As it is known that expression for equilibrium constant is as follows.
=
= 47.46
Thus, we can conclude that the equilibrium constant, Kc, for the given reaction is 47.46.
Answer: Option (d) is the correct answer.
Explanation:
The given equations as as follows.
(slow)
Therefore, overall reaction equation will be as follows.
So, cancelling the spectator ions then the equation will be as follows.
As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.
Rate law =
Hence, the reaction is first order with respect to and it is also first order reaction with respect to
.
Also, acts as a catalyst in the reaction.
Thus, we can conclude that the incorrect statement is is a catalyst.