The number of moles of NalO3 present in the deposit is 83.23 mol NaIO3.
The mass of NaNO3 deposit present is 2000. Ib Molar mass of NaNO3 is 85.03 g/mol .
Calculate the number of moles of NaNO3
present in the 2000 pounds of NaNO3.
2000 lb x (453.592 gX 1 mol NaNO3)/ 1 lbX 85.03 g
=1.067x10^4 mol NaNO3
The percentage of NaIO3 present in the NaNO3 deposit is 0.78 mol%.
Multiply the number of moles of NaNO3 with the mole percentage of the NaIO3, to get the actual number of moles of NaIO3 present in the deposit.
0.78% (1.067×10* mol NaNO3)=0.78 mol NaIO3/100 mol NaNO,
= 83.23 mol
Thus, the number of moles of NalO3 present in the deposit is 83.23 mol NaIO3
Learn more about NaIO3 here:
brainly.com/question/10249904
#SPJ4
Answer:
Particles in both liquids and gases (collectively called fluids) move randomly. ... They do this because they are bombarded by the other moving particles in the fluid. Larger particles can be moved by light, fast-moving molecules.
Explanation:
A.) SODIUM contains 11 protons........
The answer is d. Igneous rocks is indeed formed through the cooling of molten lava on the surface, making extrusive igneous rock. However, if those underground pockets of magma were to cool underneath the surface, because of its force to, it will still form intrusive igneous rock, slowly cooling.