The number of liters of 3.00 M lead (II) iodide : 0.277 L
<h3>Further explanation</h3>
Reaction(balanced)
Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)
moles of KI = 1.66
From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):
Explanation:
Helium exists in three different forms due to the phenomenon of isotopy. Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their nuclei.
- The atoms of these elements are called isotopes.
- This is why Helium can exist in three different forms.
- Isotopes have the same electronic configuration but with the same chemical properties.
Learn more:
isotopes brainly.com/question/1915462
Isotopy brainly.com/question/2593342
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The scientific notation of 420,000 is : 4.2 x 10 ^ 5
Answer:
First option:
[NH3]2 / [N2][H2]3
Explanation:
First of all we need to determine the reaction:
N₂(g) + 3H₂(g) → 2NH₃(g)
1 mol of nitrogen can combine with 3 moles of hydrogen to produce 2 moles of ammonia.
Remember that Kc has to involve Molar concentrations of products / reactants
Concentration must be elevated to the stoichiometry coefficient
Kc for the reaction is: [NH₃]² / [N₂] . [H₂]³
Answer:
In this reaction, 38.1 grams of copper will be produced.
