Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:\
B is the most correct because it provides when the outiside tempature decreases the gas temperature increases as shown in the plot data on B the other ones are not correct!
please mark brainliest and sorry for what the other user put just ignore him i just had a problem with him on another question!
The solution would be like this for this specific problem:
H0: p = p0, or <span>
H0: p ≥ p0, or
H0: p ≤ p0 </span>
find the test statistic z
= (pHat - p0) / sqrt(p0 * (1-p0) / n)
where pHat = X / n
The p-value of the test is
the area under the normal curve that is in agreement with the alternate
hypothesis. <span>
H1: p ≠ p0; p-value is the area in the tails greater than |z|
H1: p < p0; p-value is the area to the left of z
H1: p > p0; p-value is the area to the right of z </span>
Hypothesis equation:
H0: p ≥ 0.67 vs. H1: p
< 0.67
The test statistic is: <span>
z = ( 0.5526316 - 0.67 ) / ( √ ( 0.67 * (1 - 0.67 ) / 38 )
z = -1.538681 </span>
The p-value = P( Z < z
) <span>
= P( Z < -1.538681 )
<span>= 0.0619</span></span>
Range is all y-values. This would be all real numbers or (-oo,oo)
