All categories

3 years ago

The rate constant for this second‑order reaction is

Chemistry

1 answer:

o-na [289]3 years ago

3 0

Answer:

daddadaddddddddddddddddddddddddddddda

Explanation:

dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

You might be interested in

[15 Points, Heeeeelp]

Assoli18 [71]

Answer: The half reactions are given below.

Explanation:

Oxidation reactions are defined as the reactions in which a chemical species looses its electrons. The oxidation state of the specie increases.

$X\rightarrow X^{n+}+ne^-$

Reduction reactions are defined as the reactions in which a chemical species gains its electrons. The oxidation state of the specie gets reduced.

$X+ne^-\rightarrow X^{n-}$

For the given reactions:

1.) $Cl^-(aq)\rightarrow Cl_2(g)$

Here, the oxidation state is getting increased, therefore it is an oxidation reaction. The equation for this follows:

$2Cl^-(aq.)\rightarrow Cl_2(g)+2e^-$

2.) $F^-(aq.)\rightarrow F_2(g)$

Here, the oxidation state is getting increased, therefore it is an oxidation reaction. The equation for this follows:

$2F^-(aq.)\rightarrow F_2(g)+2e^-$

3.) $S(s)\rightarrow S^{2-}(aq)$

Here, the oxidation state is getting reduced, therefore it is an reduction reaction. The equation for this follows:

$S(s)+2e^-\rightarrow S^{2-}(aq)$

4.) $H_2(g)\rightarrow H^+(aq.)$

Here, the oxidation state is getting increased, therefore it is an oxidation reaction. The equation for this follows:

$H_2(g)\rightarrow 2H^+(aq.)+2e^-$

5.) $O_2(g)\rightarrow O^{2-}(aq.)$

Here, the oxidation state is getting reduced, therefore it is an reduction reaction. The equation for this follows:

$O_2(g)+4e^-\rightarrow 2O^{2-}(aq.)$

5 0

3 years ago

Name two metalloids which are liquid at room temperature. Please note you have to name two metalloids not metal or non-metal.

Ivahew [28]

Explanation:

If you like my answer than please mark me brainliest

5 0

3 years ago

The following properties are either physical or chemical. Which one is different from the rest based on those two categories?

wel

Chemical properties can only be analyzed by putting the substance through a chemical reaction, such as combustion.
Physical properties can be analyzed without altering the substance chemically. With that in mind:

Boiling point: physical
Density: physical
Ductility: physical
Heat of combustion: chemical

7 0

3 years ago

Read 2 more answers

PLS help!!!!!!!! Why are halogen atoms never a central atom?

gayaneshka [121]

They can’t have more than 8 valence electrons. Since fluorine is in group 7 it can only bound to one other molecule

3 0

3 years ago

Read 2 more answers

Compound Y has the elements C, H, N and O. It's exact mass is 91.0425. Answer the following questions. Isotope Exact Mass 1H 1.0

Talja [164]

Answer:

Six C atoms (C₆); five H atoms (H₅); one N atom (N); no O atoms

Explanation:

The rule of 13 states that the formula of a compound is a multiple n of 13 (the molar mass of CH) plus a remainder r.

MF = CₙHₙ₊ᵣ

Y has a molecular mass of 91 u

91/13 =7r0

The formula can't be C₇H₇ because a hydrocarbon must have an even number of H atoms,

The odd mass and the odd number of H atoms make it reasonable to add an N atom and subtract CH₂ (CH₂ = 14):

C₇H₇ + N - CH₂ = C₆H₅N

Check:

6C = 6 × 12.000 = 72.000 u

5H = 5 × 1.008 = 5.040

1N = 1 × 14.003 = 14.003

TOTAL = 91.043 u

This is excellent agreement with the observed mass of 91.0425 u.

There are six C atoms (C₆)

There are five H atoms (H₅)

There is one N atom (N)

There are no O atoms.

4 0

3 years ago