A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²
B. The cost of the patch to the nearest cent is 734 cents
<h3>A. How to convert 16.1 cm² to square kilometers (km²)</h3>
We can convert 16.1 cm² to km² as illustrated below:
Conversion scale
1 cm² = 1×10⁻¹⁰ km²
Therefore,
16.1 cm² = 16.1 × 1×10⁻¹⁰
16.1 cm² = 1.61×10⁻⁹ km²
Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²
<h3>B. How to determine the cost in cent</h3>
We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:
1 cm² = 0.155 in²
Therefore,
16.1 cm² = 16.1 × 0.155
16.1 cm² = 2.4955 in²
Finally, we shall the determine the cost in centas fo r llow:
- Cost per in² = $2.94 = 294 cent
- Cost of 2.4955 in² =?
1 in² = 294 cent
Therefore,
2.4955 in² = 2.4955 × 294
2.4955 in² = 734 cents
Thus, the cost of the patch is 734 cents
Learn more about conversion:
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Subtracting the mass of (flask+water) from the empty flask gives:
95.023 g - 85.135 g = 9.888 grams of water
Dividing this by the given volume of 10.00 mL water gives:
9.888 grams of water / 10.00 mL of water = 0.9888 g/mL of water
Therefore, based on this sample, the density of water is 0.9888 g/mL, which is close to the usually accepted approximation of 1 g/mL.
Answer:
<em>Friction between the hand and the wood decreased.</em>
Explanation:
The texture of the wood went from rough → smooth! This means friction between the hand and the wood was notably decreased.
According to this prompt, the carpenter used <em>sandpaper </em>against the wood. Sandpaper just so happens to be a very abrasive substance. The sandpaper polished and leveled out the wood which wore all the jutting bits away.- overall, making it much smoother and more pleasant to touch!
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Answer:
Explanation:
from the way the trees look, i would say A: Wind from the sky, it seems B: Clouds and in the distance C:Precipitation(rain)
Answer : The number of moles of ethane required will be 0.166 mole.
Explanation :
First we have to calculate the heat absorbed by water.
where,
q = heat absorbed = ?
m = mass of water = 851 g
c = specific heat of water = 
= final temperature = 
= initial temperature = 
Now put all the given values in the above formula, we get:
(1 kJ = 1000 J)
Now we have to calculate the moles of ethane required.
where,
= enthalpy of combustion of ethane = 1560.7 kJ/mol (standard value)
q = heat absorbed = 259.67 kJ
n = number of moles of ethane = ?
Therefore, the number of moles of ethane required will be 0.166 mole.
