Oxygen (O) ,Neon (Ne),Argon (Ar)
1. From the balanced equation given above, the ratio of the number of moles of the hydrocarbon and oxygen is equal to 2/7. Given that there are 2 moles of oxygen,
moles hydrocarbon = (2 moles O2)(2 moles HC / 7 moles oxygen)
Simplifying,
moles HC = 4/7 or 0.57 moles HC
Answer: 0.57 moles HC
2. The calculation for the mass of water is shown below with the dimensional analysis and conversion factors,
(30 g C2H6)1 mole C2H6/30 g C2H6)(6 molesH2O/2 moles C2H6)(18 g H2O/1 mole C2H6)
Simplifying,
mass = 54 grams of water
Answer:
sorry bro I Don't understand
Answer:
α = -0,885°
Explanation:
The specific rotation [α] is defined as:
[α] = α/ c×l <em>(1)</em>
Where α is the observed rotation, c is concentration in g/mL, and l is optical path length in dm.
A racemic mixture has no optical activity. As the solution of (R)-2-butanol is mixed with an equal volume of the racemic mixture the concentration of the original solution decreases twice. That is 1,72M/2 =<em> 0,86M. </em>This concentration in g/mL is:
0,86mol/L×
×
= <em>0,0637 g/mL</em>
Replacing in (1):

<em>α = -0,885°</em>
I hope it helps!