All categories

3 years ago

Low birth rates, death rates are constant

Physics

1 answer:

Mariana [72]3 years ago

4 0

1 is b high birth rate and death rate 2 is a low birth rates death are constant and 3 is c high birth rate and low death rate

Explanation:

You might be interested in

when you hold a warm bowl of soup the temperature of the palms of your hands increases this is an example of

bearhunter [10]

The answer is allllllllllllllllllllllllllllllllllllllllllllllllllllllllllll the way CONDUCTION

7 0

3 years ago

A perturbation in the temperature of a stream leaving a chemical reactor follows a decaying sinusoidal variation, according to t

Vsevolod [243]

Derivating the function of the temperature and equating to 0, we can find the critical points:

$T'(t)=-a\cdot5e^{-at}\cdot\sin(wt)+w\cos(wt)\cdot5e^{-at}\\\\ 0=5e^{-at}(-a\sin(wt)+w\cos(wt))$

As $5e^{-at}\neq0$ :

$0=-a\sin(wt)+w\cos(wt)\iff a\sin(wt)=w\cos(wt)\iff \\\\\sin(wt)=\dfrac{w}{a}\cos(wt)\iff \tan(wt)=\dfrac{w}{a}\iff wt=\tan^{-1}\left(\dfrac{w}{a}\right)\iff \\\\\boxed{t=\dfrac{1}{w}\tan^{-1}\left(\dfrac{w}{a}\right)}$

Replacing:

$T(t)=5e^{-at}\cdot\sin(wt)=5e^{-\frac{a}{w}\tan^{-1}\left(\frac{w}{a}\right)}\cdot\sin(\tan^{-1}\left(\dfrac{w}{a}\right))$

We can reach: $\sin(\tan^{-1}\left(\dfrac{w}{a}\right))=\dfrac{w}{\sqrt{w^2+a^2}}$

Hence:

$T(t)=\dfrac{5w}{\sqrt{w^2+a^2}}e^{-\frac{a}{w}\tan^{-1}\left(\frac{w}{a}\right)}$

4 0

3 years ago

What is the equivalent resistance of the circuit?

mezya [45]

Answer:

I=VRS=9V90Ω=0.1A

Explanation:

The equivalent resistance is the algebraic sum of the resistances (Equation 10.3. 2): RS=R1+R2+R3+R4+R5=20Ω+20Ω+20Ω+20Ω+10Ω=90Ω. The current through the circuit is the same for each resistor in a series circuit and is equal to the applied voltage divided by the equivalent resistance

5 0

3 years ago

A pet-store supply truck moves at 25.0 m/s north along a highway. inside, a dog moves at 1.75 m/s at an angle of 35.0Â° east of

koban [17]

Answer:

Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.

Explanation:

Let the east point towards positive X-axis and north point towards positive Y-axis.

Speed of truck = 25 m/s north = 25 j m/s

Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s

= (1.43 i + 1.00 j) m/s

Velocity of the dog relative to the road = 25 j + 1.43 i + 1.00 j = 1.43 i + 26.00 j

Magnitude of velocity = 26.04 m/s

Angle from positive horizontal axis = 86.85⁰

So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.

4 0

3 years ago

An equilibrium is not changed by a change in pressure. a. True b. False

alexandr1967 [171]

An equilibruium is not changed by a changed in pressure. the answer is false

7 0

3 years ago