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nadya68 [22]
4 years ago
13

Low birth rates, death rates are constant

Physics
1 answer:
Mariana [72]4 years ago
4 0

1 is b high birth rate and death rate 2 is a low birth rates death are constant and 3 is c high birth rate and low death rate

Explanation:

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A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its equilibrium position, wha
NeX [460]

Answer:

V = ω A sin ω t       can be used to describe SHM

When sin ω t = 1 (the maximum value possible)

V = ω A          at equilibrium sin ω t = 1

6 0
2 years ago
A cart travels down a ramp at an average speed of 5.00 centimeters/second. What is the speed of the cart in
Lostsunrise [7]
<span>A cart travels down a ramp at an average speed of 5.00 centimeters/second. What is the speed of the cart in miles/hour?  </span> To solve this problem we have set the conversion values to determine the product during the conversion process. <span><span>
1.   </span>1 centimeter = 0.00000621371 mile</span> <span><span>
2.   </span><span> 1 hour = 60 minutes</span></span> <span><span>3.   </span><span> 1 minute = 60 seconds</span></span>
Thus, we shall have
<span><span>1.   </span>5 cm x 0.00000621371 mile/1cm = 0.000031069 mi</span>
<span><span>2.   </span>0.000031069 seconds x 1 hr / 3600 = 0.111846815 miles / hr</span>  



8 0
4 years ago
Read 2 more answers
Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on
Likurg_2 [28]

Answer:

Reason for the difference in the ranges of the ball and the cart:

"the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

Explanation:

Assuming that the air friction is negligible.

Given that the ball lands on the ground a little before the cart.

So, the range of the ball is more than the range of the cart in the same time interval.

Let the instant speed of the cart is v m/s  at the time of throwing the ball in the vertically upward direction, so the speed of the ball in the horizontal direction = v m/s.

Let t be the total time of flight of the ball.

As the gravitational force is acting in the downward direction so it will not change the horizontal velocity of the ball.

So, the range covered by the ball = vt m.

Let u be the average speed of the cart for the time t s (same as the time of flight of ball).

So, the distance by the cart = ut m

As the range of the ball is more than the range of the cart in the same time interval, so

vt > ut \\\\\Rightarrow v>u.

So, the reason for the difference in the ranges of the ball and the cart is "the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

5 0
3 years ago
How does the orbital speed of an asteroid in a circular solar orbit with a radius of 4.0 AU compare to a circular solar orbit wi
Murrr4er [49]

Answer:

The circular solar orbital speed at 4.0AU is 1/4( one fourth) that at 1.0AU

Explanation:

am = mvr= angular momentum

am4= 4mvt

am1= mvp1

Vt=1/4vp

Vp=4vt

am1= 4mvt

am1=am4

The circular solar orbital speed at 4.0AU is 1/4 (one fourth) that at 1.0AU

6 0
4 years ago
HELP!!!
Tju [1.3M]

Answer:

A species is a group of organisms with the same GENETIC HERITAGE

Organisms from the same species can REPRODUCE with each other

8 0
3 years ago
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