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madreJ [45]
4 years ago
14

How do white dwarfs compare with supergiants, in terms of temperature and luminosity? white dwarfs are cooler and have higher lu

minosity than supergiants. white dwarfs are cooler and have lower luminosity than supergiants. white dwarfs are warmer and have higher luminosity than supergiants. white dwarfs are warmer and have lower luminosity than supergiants.
Physics
2 answers:
DerKrebs [107]4 years ago
7 0

The answer is ; white dwarfs are warmer and have lower luminosity than supergiants

The reason white dwarfs have lower luminosity is that they are way smaller in size than supergiants, even though their temperatures are way higher in comparison.

White dwarfs and red giants  are formed when the hydrogen fuel at the core of the stars is exhausted. When the star is 1 to 10 solar masses of the sun, then it forms a red  giant.



Vedmedyk [2.9K]4 years ago
5 0
The correct answer for this question is this one: 
"D. white dwarfs are warmer and have lower luminosity than supergiants." White dwarfs are also more dense than supergiants.
These are the following choices (which quite unclear above)
<span>A. white dwarfs are cooler and have higher luminosity than supergiants.
B. white dwarfs are cooler and have lower luminosity than supergiants.
C. white dwarfs are warmer and have higher luminosity than supergiants.
D. white dwarfs are warmer and have lower luminosity than supergiants.</span>
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Answer:

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Explanation:

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3 years ago
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A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
ivann1987 [24]

Answer:

v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

angle of projectile = 37°

maximum height attained formula,

H_{max}= \dfrac{v^2 sin^2(\theta)}{g}

now,

H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}

H_{max}= \dfrac{v_2^2 sin^2(\theta_2)}{g}

now, equating both the equations

\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}

\dfrac{v_2^2}{150^2}=\dfrac{sin^2(45^0)}{sin^2(37^0)}

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8 0
3 years ago
How do I solve this step by step? I’m really confused
LekaFEV [45]

Step-#1:

Ignore the wire on the right.

Find the strength and direction of the magnetic field at P,

caused by the wire on the left, 0.04m away, carrying 5.0A

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Write it down.


Step #2:

Now, ignore the wire on the left.

Find the strength and direction of the magnetic field at P,

caused by the wire on the right, 0.04m away, carrying 8.0A

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Write it down.


Step #3:

Take the two sets of magnitude and direction that you wrote down

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3 years ago
A closed pipe creates a
lina2011 [118]

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375 hz

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Trust me

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3 years ago
What must be the acceleration of a train in order for it to stop 12 m/s in a distance if 541 m
earnstyle [38]

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

Lets explain how to solve the problem

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

We want to find its acceleration

The acceleration will be negative quantity because the train reduced its

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We need rule contains velocity, acceleration and distance

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Divide both sides by 1082

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<em>The acceleration of the train must be - 0.133 m/s²</em>

3 0
3 years ago
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