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3 years ago

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As part of your job you are asked to make 1 liter of a 0.5 molar sucrose solution. how much sucrose (c12h22o11) do you need? use

the information below listing the number of protons, neutrons, and electrons in each element.

1 answer:

kakasveta [241]3 years ago

6 0

Answer:- 171 g

Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.

We know that molarity is moles of solute per liter of solution.

If molarity and volume is given then, moles of solute is molarity times volume in liters.

moles of solute = molarity* liters of solution

moles of solute = 0.5*1 = 0.5 moles

To convert the moles to grams we multiply the moles by molar mass.

Molar mass of sucrose = 12(12) + 22(1) + 11(16)

= 144 + 22 + 176

= 342 grams per mol

grams of sucrose required = moles * molar mass

grams of sucrose required = 0.5*342 = 171 g

So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.

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According to the ICE table for the given reaction,

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Change: -x +x +x

Equilibrium: 0.58 - x x x

So,

$K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}$

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$x^{2} = 1.59 \times 10^{-7} \times (0.58 - x)$

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= 0.579 M

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$HSO^{2-}_{3} + H_{2}O \rightleftharpoons H_{2}SO_{3} + OH^{-}$

Initial: 0.0003

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$K_{b} = \frac{x^{2}}{0.0003 - x}$

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As, x <<<< 0.0003. So, we can neglect x.

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= $0.00214 \times 10^{-13}$

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= $\frac{10^{-14}}{0.0003}$

= $3.33 \times 10^{-11}$ M

Thus, we can conclude that the concentration of spectator ion is $3.33 \times 10^{-11}$ M.

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