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3 years ago

What are the reactants in a neutralization reaction? two elements an acid and a base an element and a compound a salt and water

Chemistry

2 answers:

LenKa [72]3 years ago

8 0

Answer: Option (b) is the correct answer.

Explanation:

A reaction in which an acid reacts with base and results in the formation of salt and water is known as a neutralization reaction.

For example, $2HCl + CaOH \rightarrow CaCl_{2} + H_{2}O$ is a neutralization reaction as salt here is calcium chloride.

Thus, we can conclude that the reactants in a neutralization reaction are an acid and a base.

Vitek1552 [10]3 years ago

5 0

ok thank you for elaborating and you are correct in a neutralization reaction the reactants are the acid and base. the salt and water would be the product and the two elements could be anything meaning that it is most likely a mixture

Hope this helps

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4 years ago

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A chemist makes up a solution by dissolving 42.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 259 mL. To

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The molar mass of Mg(NO₃)₂, 148.3 g/mol.

Explanation:

Step 1: Given data

Mass of Mg(NO₃)₂ (solute): 42.0 g

Volume of solution: 259 mL = 0.259 L

Step 2: Calculate the moles of solute

To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.

42.0 g × 1 mol/148.3 g = 0.283 mol

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3 years ago

Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?

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Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

C + O2 ------> CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2.

 86.5 g CO = 1.966 moles CO2
44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel.

1.966 moles CO2 x 1 mole C x 12 g C = 23.59 g C
1 mole CO2 1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams.

25.0 g - 23.59 g = 1.41 grams Hydrogen

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen.

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel,

Carbon: 1.966 mol = 1.408 x 5 (factor) = 7
1.396 mol

Hydrogen: 1.396 mol = 1.00 x 5 (factor) = 5
1.396 mol

Thus, the empirical formula is C7H5

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4 years ago

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