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Alenkasestr [34]

3 years ago

12

You are attempting to identify two mystery metals. Explain what different properties would be helpful in identifying them and ho

w they would Aid in identification of the metals.

2 answers:

kirill [66]3 years ago

8 0

The hardness, and luster of a metal can determine the indentification.

Valentin [98]3 years ago

3 0

Answer:

The Hardness of the Metal

Explanation:

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Why does liquids rate of evaporation increase when the liquid is heated

ivann1987 [24]

Boiling liquids that want to escape gas

4 0

3 years ago

If this is a p1000 micropipette, then this is set to dispense [ Select]ul. If this is a p10

mariarad [96]

Answer:

1000 µL; 10 µL

Explanation:

A p1000 micropipet is set to dispense 1000 µL.

A p10 micropipet set to dispense 10 µL.

3 0

3 years ago

Examine the ph scale below. How does household bleach compare to household ammonia?

Kazeer [188]

Answer is: household ammonia has 10 times higher H⁺ concentration.

1) pH(household ammonia) = 11.5.

pH = -log[H⁺], approximately the negative of the base 10 logarithm of the molar concentration of hydrogen ions.

[H⁺] = 10∧(-pH).

[H⁺] = 10∧(-11.5).

[H⁺] = 3.16·10⁻¹² M; concentration of hydrogen ions.

2) pH(household bleach) = 12.5.

[H⁺] = 10∧(-12.5).

[H⁺] = 3.16·10⁻¹³ M.

3) 3.16·10⁻¹² M / 3.16·10⁻¹³ M = 10.

6 0

3 years ago

Read 2 more answers

!!!!!!!!!!!!!!!????<br> hElP!!!!!!!!!!!!

kakasveta [241]

I think the answer is transparent and translucent

5 0

3 years ago

Read 2 more answers

A mixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 K and a total pressure of 100 kPa. If the vapo

AURORKA [14]

Answer : The correct option is, (b) 0.087

Explanation :

The formula used for relative saturation is:

$\text{Relative saturation}=\frac{P_A}{P_A^o}$

where,

$P_A$ = partial pressure of ethyl acetate

$P_A^o$ = vapor pressure of ethyl acetate

Given:

Relative saturation = 50 % = 0.5

Vapor pressure of ethyl acetate = 16 kPa

Now put all the given values in the above formula, we get:

$0.5=\frac{P_A}{16kPa}$

$P_A=8kPa$

Now we have to calculate the molar saturation.

The formula used for molar saturation is:

$\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}$

and,

P(vapor free) = Total pressure - Vapor pressure

P(vapor) = $P_A$ = 8 kPa

So,

P(vapor free) = 100 kPa - 8 kPa = 92 kPa

The molar saturation will be:

$\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}$

$\text{Molar saturation}=\frac{8kPa}{92kPa}=0.087$

Therefore, the molar saturation is 0.087

5 0

3 years ago