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Alenkasestr [34]
3 years ago
12

You are attempting to identify two mystery metals. Explain what different properties would be helpful in identifying them and ho

w they would Aid in identification of the metals.
Chemistry
2 answers:
kirill [66]3 years ago
8 0
The hardness, and luster of a metal can determine the indentification.
Valentin [98]3 years ago
3 0

Answer:

The Hardness of the Metal

Explanation:

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Why does liquids rate of evaporation increase when the liquid is heated
ivann1987 [24]
Boiling liquids that want to escape gas
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3 years ago
If this is a p1000 micropipette, then this is set to dispense [ Select]ul. If this is a p10
mariarad [96]

Answer:

1000 µL; 10 µL  

Explanation:

A p1000 micropipet is set to dispense 1000 µL.

A p10 micropipet set to dispense 10 µL.

3 0
3 years ago
Examine the ph scale below. How does household bleach compare to household ammonia?
Kazeer [188]

Answer is: household ammonia has 10 times higher H⁺ concentration.

1) pH(household ammonia) = 11.5.

pH = -log[H⁺], approximately the negative of the base 10 logarithm of the molar concentration of hydrogen ions.

[H⁺] = 10∧(-pH).

[H⁺] = 10∧(-11.5).

[H⁺] = 3.16·10⁻¹² M; concentration of hydrogen ions.

2) pH(household bleach) = 12.5.

[H⁺] = 10∧(-12.5).

[H⁺] = 3.16·10⁻¹³ M.

3) 3.16·10⁻¹² M / 3.16·10⁻¹³ M = 10.

6 0
3 years ago
Read 2 more answers
!!!!!!!!!!!!!!!????<br> hElP!!!!!!!!!!!!
kakasveta [241]
I think the answer is transparent and translucent
5 0
3 years ago
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A mixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 K and a total pressure of 100 kPa. If the vapo
AURORKA [14]

Answer : The correct option is, (b) 0.087

Explanation :

The formula used for relative saturation is:

\text{Relative saturation}=\frac{P_A}{P_A^o}

where,

P_A = partial pressure of ethyl acetate

P_A^o = vapor pressure of ethyl acetate

Given:

Relative saturation = 50 % = 0.5

Vapor pressure of ethyl acetate = 16 kPa

Now put all the given values in the above formula, we get:

0.5=\frac{P_A}{16kPa}

P_A=8kPa

Now we have to calculate the molar saturation.

The formula used for molar saturation is:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

and,

P(vapor free) = Total pressure - Vapor pressure

P(vapor) = P_A = 8 kPa

So,

P(vapor free) = 100 kPa - 8 kPa = 92 kPa

The molar saturation will be:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

\text{Molar saturation}=\frac{8kPa}{92kPa}=0.087

Therefore, the molar saturation is 0.087

5 0
3 years ago
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