Answer:
the number of molecules in 7g nitrogen
Ans) 7 gram of Nitrogen contains 1.5×10^23 molecules =1.5e+23
Explanation:
It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.
Number of millimoles = Molarity × Volume
As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.
Therefore, putting the given values into the above formula as follows.
Number of millimoles = Molarity × Volume
= 0.485 M × 500 mL
= 242.5
Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.
Answer:
D. 34.5g
Explanation:
Using the following formula to calculate the mass of 1.5moles of sodium (Na);
Mole = mass/molar mass
Molar mass of Na = 23g/mol
mass = mole × molar mass
Mass of Na = 1.5mol × 23g/mol
Mass of Na = 34.5g
I believe its A "Air is made up of about 21% oxygen and 78% nitrogen. In this solution, oxygen is the solute and nitrogen is the solvent.
The physical process of evaporation involves the heat absorbing and the status of the substance changing. The status of this substance changes form liquid to gas.
