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just olya [345]
3 years ago
11

The formation of soil is primarily the result of

Chemistry
2 answers:
Norma-Jean [14]3 years ago
3 0
<span>he formation of soil is primarily the result of </span>decomposition.
fomenos3 years ago
3 0

Answer:

<u>Formation of soil:</u>

The soil formation basically results from the weathering of rocks.

Explanation:

<u>Weathering of rocks and the formation of soil:</u>

The soil is mainly formed from different nutrients, and minerals. As different living organisms lives inside the soil. Weathering of rocks leads to deposition  of nutrients, minerals, and water molecules inside the different layers. The process takes place when the different molecules are carried from one point to the another on the surface of the planet, this results in the creation of different layers of soil over time.

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Which three temperature readings all mean the same thing?
allochka39001 [22]

Answer: The correct answer is D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.

Explanation:

Conversion of degree Celsius to Kelvin :

K=^oC+273

Conversion of degree Celsius to degrees Fahrenheit :

^oF=(\frac{9}{5}\times ^oC)+32

By using these two conversion factors, we get the three temperature readings all mean the same thing.

For option A :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option B :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option C :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

For option D :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

From the given options, only option (D) is correct.

Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

Hope this helps!

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C₇H₆O₂ + O₂ --&gt;CO₂ +H₂O Find the chemical reaction
lions [1.4K]

Answer:

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Explanation:

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In the compound H2O, the electrons in the bonds are unequally shared between oxygen and hydrogen, forming ____. (1 point)
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<span>polar bonds due to high difference . In electronegativity of oxygen and hydrogen.</span>
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