According to Osmotic pressure equation:
π = i M R T
When π =0.307 atm & M = 0.01 mol & R (constant)= 0.0821 L-atom/mol-K &
T= 22+273 = 295 Kelvin
So Van't half vector i = π / (MRT)
= 0.307 / (0.01 * 0.0821 * 295)
= 1.27
When there is no dissociation, i = no. of moles of Hf in 1 L of solution = (1-X)
and when there is a complete dissociation so it is equal 2X according to this equation
HF(aq) + H2O (L) ⇆ H3O (aq) + F (aq)
(1-X) X X
∴ i = (1-X) + (2x)
1.27 = 1+X
∴X= 1.27 - 1 = 0.27
∴ the percent ionization of the acid X = 27 %
Insulation wraps because independent is the variable you are changing to affect the dependent variable (what you are measuring)
The PRODUCT is found on the right side of the arrow in a chemical reaction.
Answer:
positively charged elctrons
The chemical equation would be:
2NO(g) + O2(g) --> 2NO2 (g)
<span>At equilibrium state, the partial pressure of the gases would be as follows : </span>
<span>NO = 522 - 2x </span>
<span>O2 = 421 - x </span>
<span>NO2 = 2x </span>
<span>- - - - - - - - - - - - -</span>
<span>943 - x = 748 </span>
<span>x = 195</span>
Calculating for Kp,
<span>Kp = (NO2)^2/ ((NO)^2 * (O2)) </span>
<span>Kp = (2 * 195)^2/ ((522 - 2 * 195)^2 * (421 - 195)) </span>
<span>Kp = 0.0386 </span>
