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kow [346]
3 years ago
10

Solve question 4a least reactive to most reactive

Chemistry
1 answer:
denis23 [38]3 years ago
7 0
Nickel (II) oxide, iron (III) oxide, chromium (III) oxide, magnesium oxide
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In atmospheric chemistry, the following chemical reaction converts SO2, the predominant oxide of sulfur that comes from combusti
Misha Larkins [42]

Answer:

Explanation:

From the given information;

The chemical reaction can be well presented as follows:

\mathtt{SO_{2(g)} + \dfrac{1}{2}O_{2(g)} }  ⇄ \mathtt{3SO_{2(l)}}

Now, K is known to be the equilibrium constant and it can be represented in terms of each constituent activity:

i.e

K = \dfrac{a_{so_3}}{a_{so_2} a_{o_2}^{\frac{1}{2}}}

However, since we are dealing with liquids solutions;

K = \dfrac{1}{\dfrac{Pso_2}{P^0}\Big ( \dfrac{Po_2}{P^0} \Big)^{1/2}}   since the activity of a_{so_3} is equivalent to 1

Hence, under standard conditions(i.e at a pressure of 1 bar)

K = \dfrac{1}{Pso_2Po_2^{1/2}}

(b)

From the CRC Handbook, we are meant to determine the value of the Gibb free energy by applying the formula:

\Delta _{rxn} G^o = \sum \Delta_f \ G^o (products) - \sum \Delta_fG^o (reactants) \\ \\ = (1) (-368 \ kJ/mol) - (\dfrac{1}{2}) (0) - ((1) (-300.13 \ kJ/mol)) \\ \\ = -368 \ kJ/mol + 300.13 \ kJ/mol \\ \\  \simeq -68 \ kJ/mol

Thus, for this reaction; the Gibbs frree energy = -68 kJ/mol

(c)

Le's recall that:

At equilibrium, the instantaneous free energy is usually zero &

Q(reaction quotient) is equivalent to K(equilibrium constant)

So;

\mathtt{\Delta _{rxn} G = \Delta _{rxn} G^o + RT In Q}

\mathtt{0- \Delta _{rxn} G^o = RTIn K } \\ \\ \mathtt{ \Delta _{rxn} G^o = -RTIn K }  \\ \\  K = e^{\dfrac{\Delta_{rxn} G^o}{RT}} \\ \\  K = e^{^{\dfrac{67900 \ J/mol}{8.314 \ J/mol \times 298 \ K}} }

K =7.98390356\times 10^{11} \\ \\  \mathbf{K = 7.98 \times 10^{11}}

(d)

The direction by which the reaction will proceed can be determined if we can know the value of Q(reaction quotient).

This is because;

If  Q < K, then the reaction will proceed in the right direction towards the products.

However, if Q > K , then the reaction goes to the left direction. i.e to the reactants.

So;

Q= \dfrac{1}{Pso_2Po_2^{1/2}}

Since we are dealing with liquids;

Q= \dfrac{1}{1 \times 1^{1/2}}

Q = 1

Since Q < K; Then, the reaction proceeds in the right direction.

Hence, SO2 as well O2 will combine to yield SO3, then condensation will take place to form liquid.

8 0
3 years ago
What is the density of an object that has a mass of 28.1g and a volume of 96.2mL? Select the correct answer below: 0.292g/mL 270
kakasveta [241]

Answer:

0.292 g/mL.

Explanation:

From the question given above, the following data were obtained:

Mass of object = 28.1 g

Volume of object = 96.2 mL

Density of object =..?

Density of an object is simply defined as the mass of the object per unit volume of the object. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the object as follow:

Mass of object = 28.1 g

Volume of object = 96.2 mL

Density of object =..?

Density = mass / volume

Density = 28.1 / 96.2

Density of object = 0.292 g/mL

Thus the density of the object is 0.292 g/mL

3 0
3 years ago
The electronegativity values of fluorine, oxygen, and hydrogen are compared in the table. Comparison of Electronegativity Elemen
Dvinal [7]

The hydrogen bonding in H₂O is stronger than that of HF

Explanation:

Hydrogen bonds are special dipole-dipole attraction in which electrostatic attraction is established between hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

  • The strength of hydrogen bonds depends on the how electronegative an atom is.
  • Electronegativity refers to the tendency of an atom to gain electrons.
  • The higher the value, the higher the tendency.
  • This why oxygen with a higher electronegativity will form a stronger hydrogen bond with hydrogen compared to fluorine.

Learn more:

hydrogen bond brainly.com/question/12408823

#learnwithBrainly

4 0
3 years ago
How would changing the proportions of substance in an alloy change its properties?
sammy [17]
An alloy is a mixture of two or more metals which is produced with a specific proportion between metals. So, if the proportion is changed the physical characteristic would be changed as well. For example, brass musical instruments are made of brass which is a mixture (an alloy) of zinc and copper in a specific proportion. If you change a proportion, you will change the physical characteristic of brass musical instruments, and a sound they produce will be different. 
4 0
3 years ago
A 2.26 M solution of KOH is prepared. Calculate the moles and mass of solute present in a 15.2-mL sample of this solution. The m
kenny6666 [7]

Answer:

0.0344 moles and 1.93g.

Explanation:

Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:

<em>Moles KOH:</em>

15.2mL = 0.0152L * (2.26mol / L) = 0.0344moles

<em>Mass KOH:</em>

0.0344 moles * (56.11g/mol) = 1.93g of KOH

7 0
3 years ago
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