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vodomira [7]
3 years ago
5

Johnathan has a bag full of 14 balls to sell. He sells the baseballs for $2 dollars and the volleyballs for $5 and earns a total

of $43. If the baseballs are represented by x and the volleyballs are represented by y, which of the following systems of equations can be used to calculate the number of baseballs and volleyballs sold?
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0
2x + 5y = 43 
x+y=14
Awnser x=9 and y=5
(2 x 9) + (5 x 5) = 43
5+9=14
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crimeas [40]
I’d say the answer is 18 because dino nuggies are being killed every day
6 0
3 years ago
Heather left the hospital and drove toward the desert at an average speed of 35 km/h. Danielle left sometime later driving in th
elena55 [62]

Answer:

Danielle drove 3 hours

Step-by-step explanation:

Suppose Heather moved in the x direction.

Then Danielle moved in the opposite direction, that is, she moved in the -x direction.

Let's call V_1, x_1, t_1 at the speed, distance and time that I code Heather

Let's call V_2, x_2, t_2 at the speed, distance and time Danielle codes.

Observe the following diagram:

(x) Heather <------ x_1 --------- hospital ---------- x_2 -----------> Danielle (-x)

So:

V_1 = 35\ km/h

t_1 = 4\ h

V_2 = 50\ km/h

We know that after 4 hours the distance between Heather and Danielle was 290 km.

That is to say:

x_2 + x_1 = 290\ km/h

We know that x_1= v_1t_1

x_1 = 35(4)

x_1 = 140\ km

We already know x_1, the distance from the hospital to Heather, so we can find x_2 and thus know t_2

So:

x_2 = 290 - 140\\\\x_2 = 150\ km

Then:

t_2 = \frac{x_2}{v_2}\\\\t_2 = \frac{150}{50}\\\\t_2 = 3\ h

7 0
3 years ago
What percent is equivalent to 1/25?​
oksano4ka [1.4K]

Answer:

4%

25 x FOUR is 100 so 4 is the answer

5 0
3 years ago
Read 2 more answers
ABC is similar to ADEF. Find x. GEOMETRY
azamat

The value of x in the given diagram is 10

<h3>Similar triangles </h3>

From the question, we are to determine the value of the side labeled x

First, we will find the value of side |BC|

By the <em>Pythagorean theorem</em>, we can write that

|BC|² = 12² + 16²

|BC|² = 144 + 256

|BC|² = 400

|BC| = √400

|BC| = 20

Now,

Since ΔABC and ΔDEF are similar, we can write that

|BC| / |EF| = P ΔABC / P ΔDEF

But,

P ΔABC = 12 + 16 + 20 = 48

Thus,

|BC| / |EF| = P ΔABC / P ΔDEF becomes

20/ |EF| = 48/24

20/x = 2

x = 20/2

x = 10

Hence, the value of x in the given diagram is 10

Learn more on Similar triangles here: brainly.com/question/24085502

#SPJ1

6 0
2 years ago
Point A is at (2,-8) and the point C is at (-4,7). Find the coordinates of point B on AC such that the ratio of AB to BC is 2:1.
pentagon [3]

Answer:

The coordinates of point B are (-2, 2)

Step-by-step explanation:

We have two points: A and C.

The coordinates for A are (2, -8) and the coordinates for C are (-4, 7).

We have to find the coordinates of the point B, that satisfies the condition that the distance AB is 2 times the distance BC.

We also know that B is a point of the line AC.

We can calculate the line AC as a linear function y=mx+b.

The slope m is:

m=\dfrac{y_c-y_a}{x_c-x_a}=\dfrac{7-(-8)}{-4-2}=\dfrac{15}{-6}=-2.5

Then, the y-intercept b can be calculated using the coordinates of one of the points, in this case point A:

y=-2.5x+b\\\\b=y_a+2.5x_a=-8+2.5*2=-8+5=-3

Then, we know that B is a point of the linear function y=-2.5x-3, within the range x ∈ (-4; 2).

To have a ratio AB to BC of 2 to 1, we can divide the length of the line AC in 3 parts, and the point B will be located in the  end of the segment nearer to point C.

In the picture attached, you can see the division of the segment AC in three parts and the location of point B=(x, y).

Applying the Thales theorem, we can divide the segment in the y-axis in three and calculate y, and the same for the x-axis.

Then, the coordinate y for the point B is:

y=y_c-(y_c-y_a)/3\\\\y=7-[7-(-8)]/3=7-15/3=7-5=2\\\\\\x=x_c-(x_c-x_a)/3\\\\x=-4-(-4-2)/3=-4-(-6)/3=-4+2=-2

Then, the point B has coordinates (-2, 2).

We can verify the distances as:

AB=\sqrt{(2-(-2))^2+((-8)-2)^2}=\sqrt{16+100}=\sqrt{116}\\\\\\BC=\sqrt{((-2)-(-4))^2+(2-7)^2}=\sqrt{4+25}=\sqrt{29}\\\\\\\dfrac{AB}{BC}=\dfrac{\sqrt{116}}{\sqrt{29}}=\sqrt{\dfrac{116}{29}}=\sqrt{4}=2

4 0
3 years ago
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