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Naily [24]
3 years ago
10

What is the value of x in the equation 1/5x - 2/3y =30 when y =15 ?

Mathematics
2 answers:
SpyIntel [72]3 years ago
4 0
Solve for x:
x/5 - 10 = 30
Put each term in x/5 - 10 over the common denominator 5: x/5 - 10 = x/5 - (50)/5:
x/5 - (50)/5 = 30
x/5 - (50)/5 = (x - 50)/5:
(x - 50)/5 = 30
Multiply both sides of (x - 50)/5 = 30 by 5:
(5 (x - 50))/5 = 5×30
(5 (x - 50))/5 = 5/5×(x - 50) = x - 50:
x - 50 = 5×30
5×30 = 150:
x - 50 = 150
Add 50 to both sides:
x + (50 - 50) = 50 + 150
50 - 50 = 0:
x = 150 + 50
150 + 50 = 200:
Answer:  x = 200
hichkok12 [17]3 years ago
4 0
\frac{1}{5} *x- \frac{2}{3} *y=30

x/5 - 2*15/3=30

x/5 - 30/3 = 30

x/5 - 10 = 30

x/5 = 40

x = 40 x 5

x = 200
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\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}

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                      First, add 6x on both sides:

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<h3>Good luck.</h3>

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5. Given (x + 1) and (x-3) are factors of P(x) = x4-5x³-7x² + cx + d. Determine the values
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By concepts of polynomials and systems of linear equations, the constants c and d of the expression p(x) = x⁴ - 5 · x³ - 7 · x² + c · x + d are 29 and 30.

<h3>How to determine the missing coefficients of a quartic equation</h3>

A value x is a root of a polynomial if and only if p(x) = 0. We must replace the given equation with the given roots and solve the resulting system of <em>linear</em> equations:

(- 1)⁴ - 5 · (- 1)³ - 7 · (- 1)² + (- 1) · c + d = 0    

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The solution of this system is c = 29 and d = 30.

By concepts of polynomials and systems of linear equations, the constants c and d of the expression p(x) = x⁴ - 5 · x³ - 7 · x² + c · x + d are 29 and 30.

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