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BaLLatris [955]
4 years ago
15

CAN YOU GUYS HELP ME FOR #10

Mathematics
2 answers:
SVETLANKA909090 [29]4 years ago
5 0
You’ve been asleep for 22 years , multiply
Tema [17]4 years ago
4 0

Answer:

31

Step-by-step explanation:

You might be interested in
Write the general equation for the circle that passes through the points:
kiruha [24]

Answer:

The answer to your question is     x² + y² - 8x - 6y = 0

Step-by-step explanation:

Data

P (1, 7)

Q (8, 6)

R (7, -1)

Use the general equation of the Circle

                            x² + y² + Dx + Ey + F = 0

Process

1.- Substitute each point in the general equation and simplify

For P                                  

                          (1)² + (7)² + D + 7E + F = 0

                            1 + 49 + D + 7E + F = 0

                                 50 + D + 7E + F = 0

                                       D + 7E + F = -50             Equation l

For Q

                           (8)² + (6)² + 8D + 6E + F = 0

                            64 + 36 + 8D + 6E + F = 0

                            100 + 8D + 6E + F = 0

                                    8D + 6E + F = -100         Equation ll

For R

                           (7)² + (-1)² + 7D - E + F = 0

                           49 + 1 + 7D - E + F = 0

                                50 + 7D - E + F = 0

                                         7D - E + F = -50       Equation lll

Solve the system of equations, I do not include the process but the solutions are

D = -8   E = -6   F = 0

-Substitution

                       x² + y² - 8x - 6y = 0

6 0
3 years ago
A comet travels along a parabolic path around the Sun. The Sun is the focus of the path. When the comet is at the vertex of the
AlladinOne [14]
Remember that for a function of the form y=a x^{2}, a parabola, the focus will be: (0, \frac{1}{4a} ).
We know that the vertex of the parabola is (0,0), and the sun is the focus of the parabola; we also know that the focus is in the positive y-axis and when the comet is as its vertex, the distance between them is 60'000.000 km; therefore the focus of our parabola is (0, 60'000.000).
Now that we know the focus, we can find a using the focus of the parabola:
\frac{1}{4a} =60'000.000
1=(60'000.000)(4a)
1=240'000.000a
a= \frac{1}{240'000.000}

Now, the only thing left is replacing the value of a in our equation y=a x^{2}:
y=( \frac{1}{240'000.000)} ) x^{2}
y= \frac{ x^{2} }{240'000.000}
 
We can conclude that the equation that represents the path of the comet is y= \frac{ x^{2} }{240'000.000}

5 0
3 years ago
Find g(1) if g(x) = x^2 + 1.<br><br> 2<br> 3<br> 4<br><br> Answer is NOT 3.
kirza4 [7]
2 because 1x1=1 and 1+1=2
7 0
4 years ago
Read 2 more answers
How many millimeters are in 1 meter
melisa1 [442]
The answer is 1000 millimeters in one meter
3 0
3 years ago
You are trying to figure out how many gumballs you need to fill a 7.3 x 5.0 x 9.4 rectangular box for Halloween. Each gumball ha
riadik2000 [5.3K]

According to the calculations made, 410 gumballs will be needed to fill the box.

Since you are trying to figure out how many gumballs you need to fill a 7.3 x 5.0 x 9.4 rectangular box for Halloween, and each gumball has a radius of 1/2 in, if the packing density for spheres is 5/8 of the volume will be filled with gumballs while the rest will be air how many gumballs will be needed, to determine this amount the following calculation must be performed:

  • (Volume of box x 5/8) / volume of gumballs = Amount of gumballs  
  • Volume of a sphere = 4/3 x 3.14 x (radius x radius x radius)  
  • Volume of a gumball = 4/3 x 3.14 x (0.5 x 0.5 x 0.5) = 0.5235 inches  
  • ((7.3 x 5 x 9.4) x 5/8) / 0.523 = X
  • (343.1 x 5/8) / 0.523 = X
  • 214.4375 / 0.523 = X
  • 410 = X

Therefore, 410 gumballs will be needed to fill the box.

Learn more in brainly.com/question/1578538

4 0
3 years ago
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