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3 years ago

What is the number of solutions in this system?

Mathematics

1 answer:

solniwko [45]3 years ago

7 0

I could answer but u have no picture of the question

Brainliest ?

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Find the measure of each acute angle in the figure.

Artist 52 [7]

Answer:

Angle 1 = 46°

Angle 2 = 44°

Step-by-step explanation:

Given:

Angle 1 = (4x - 2)°

Angle 2 = (3x + 8)°

Angle 3 = 90°

Find:

All acute angle

Computation:

Using angle sum property

Angle 1 + Angle 1 + Angle 1 = 180°

(4x - 2)° + (3x + 8)° + 90° = 180°

7x + 6 = 90

7x = 84

x = 12°

So,

Angle 1 = (4x - 2)° = 4(12) - 2 = 46°

Angle 2 = (3x + 8)° = 3(12) + 8 = 44°

4 0

3 years ago

Divide the polynomials.

Mnenie [13.5K]

Answer:

$\dfrac{3x^3+x-11}{x+1}=3x^2-3x+4-\dfrac{15}{x+1}$

Step-by-step explanation:

We want to determine the result of the quotient: $\dfrac{3x^3+x-11}{x+1}$

We follow the procedure of long division which is set out int he table below.

$\left|\begin{array}{c|c}&3x^2-3x+4\\-----&-----\\x+1&3x^3+x-11\\Subtract&-(3x^3+3x^2)\\&------\\&-3x^2+x-11\\Subtract&-3x^2-3x\\&------\\&4x-11\\Subtract&4x+4\\&------\\&-15\end{array}\right|$

Therefore:

$\dfrac{3x^3+x-11}{x+1}=3x^2-3x+4-\dfrac{15}{x+1}$

3 0

4 years ago

What is 9=4t+(-7t) how would I find the value of t

posledela

4t+(-7t) is the same as you saying 4t-7t, so 4t-7t= -3t. 9=-3t, divide each side by -3 and t is equal to -3

6 0

4 years ago

Read 2 more answers

Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.

jek_recluse [69]

Answer:

$\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)$

Step-by-step explanation:

Let $X$ be a set of all students in your class. The set $X$ is the domain. Denote

$C(x) - ' \text{$x $ has a cat}'\\D(x) - ' \text{$x$ has a dog}'\\F(x) - ' \text{$x$ has a ferret}'$

$\mathbf{a)}$

Consider the statement 'A student in your class has a cat, a dog, and a ferret'. This means that $\exists x \in X$ so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)$

$\mathbf{b)}$

Consider the statement 'All students in your class have a cat, a dog, or a ferret.' This means that $\forall x \in X$ at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)$

$\mathbf{c)}$

Consider the statement 'Some student in your class has a cat and a ferret, but not a dog.' This means that $\exists x \in X$ so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)$

$\mathbf{d)}$

Consider the statement 'No student in your class has a cat, a dog, and a ferret..' This means that $\forall x \in X$ none of the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

$\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)$

$\mathbf{e)}$

Consider the statement ' For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.'

This means that for each of the statements C, F and D there is an element from the domain $X$ so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left((\exists x\in X)C(x) \right) \wedge \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)$

5 0

4 years ago

One of those fraction type questions, that I don’t know

Yuliya22 [10]

Answer:

Step-by-step explanation:

To solve this problem, we need to first find the ratio of numbers less than four to total numbers.

There are 3 numbers on the wheel less than 4 (1, 2, and 3). There are 8 total numbers, meaning the ratio of numbers less than 4 to total numbers is 3:8.

Now, we need to find the probability of spinning a white number. There are 3 white numbers on the wheel (3, 5, 8). However, one of these numbers (3) is less than 4, so it is already accounted for in the previous ratio. There are 2 numbers left, meaning the ratio of remaining white numbers to total numbers is 2:8.

Adding this to the original equation, we get 5:8. As a fraction, 5:8 = 5/8. The answer that correctly highlights this is C.

7 0

3 years ago