3x² + 5x - 2 = 0
3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
3x(x + 2) - 1(x + 2) = 0
(3x - 1)(x + 2) = 0
3x - 1 = 0 or x + 2 = 0
+ 1 + 1 - 2 - 2
3x = 1 or x = -2
3 3 1 1
x = ¹/₃ or x = -2
f(x) = 3x² + 5x - 2
f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
f(¹/₃) = ¹/₃ - ¹/₃
f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)
f(x) = 3x² + 5x - 2
f(-2) = 3(-2)² + 5(-2) - 2
f(-2) = 3(4) - 10 - 2
f(-2) = 12 - 12
f(-2) = 0
(x, f(x)) = (-2, 0)
Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
Oblique Asymptote: No Asymptotes
Answer:
-7x+14y-35
Step-by-step explanation:
Answer:
the graph of y^2+3x=0 is symmetric with respect to which axis
Step-by-step explanation:
Answer:
y=-1
From where the line crosses the y axis, it goes up 1 and over 1 from each plane although its moving to the left from 0 every time. This means the slope is negative.
In the equation y=mx+b, b is the y intercept and m is the slope
plugin the info and you get y=-1x+0 or
y=-1x
Step-by-step explanation:
First subtract y from both sides to isolate the variable.
25 = 2y-2
Next, add 2 to both sides.
27 = 2y
Last, divide by 2.
13.5 = y
