Answer:
The peak current carried by the axon is 5.85 x 10⁻⁸ A
Explanation:
Given;
distance of the field from the axon, r = 1.3 mm
peak magnetic field strength, B = 9 x 10⁻¹² T
To determine the peak current carried by the axon, apply the following equation;
where;
B is the peak magnetic field
r is the distance of the magnetic field from axon
μ is permeability of free space = 4π x 10⁻⁷
I is the peak current
Re-arrange the equation and solve for "I"
Therefore, the peak current carried by the axon is 5.85 x 10⁻⁸ A
Longer Health. Maybe give more options?
Answer:A.
only when a nonzero net force is applied to the object.
Explanation:
Answer:
Part a)
Part b)
Explanation:
Part A)
As we know by Force equation on the losing player
so we will have
Part b)
As we know that the winning player is also moving with same acceleration
so we will have