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3 years ago

A 40.0 kg block of lead is heated from -25°C to 200°C.

Physics

1 answer:

irga5000 [103]3 years ago

4 0

Answer:

B. 1,170,000 J

Explanation:

Given;

mass of lead block, m = 40 kg

initial temperature, t₁ = -25 ⁰C

final temperature, t₂ = 200 ⁰C

The heat absorbed the lead block is calculated as;

H = mcΔt

where;

c is the specific heat capacity of lead = 130 J/kg⁰C

H = 40 x 130 x (200 - (-25))

H = 40 x 130 x (200 + 25)

H = 40 x 130 x 225

H = 1,170,000 J

Therefore, the heat absorbed the lead block is 1,170,000 J

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neonofarm [45]

The work done by the water at the constant pressure is $-4.52 \times 10^6 \ J$ .

<h3>Heat required to boil the water</h3>

The heat required to boil the water is calculated as follows;

$Q = mL_v\\\\$

where;

$L_v$ is the heat of vaporization of water = 22.6 x 10⁵ J/kg
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The work done by the water at the constant pressure is equal to the heat gained by the water.

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Learn more about first law of thermodynamics here: brainly.com/question/2965070

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3 years ago

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PolarNik [594]

Answer:

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3 years ago

A 1.0-kg standard cart collides on a low-friction track with cart A. The standard cart has an initial x component of velocity of

Andru [333]

Answer:

Explanation:

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In this case, the system consists of two carts.

At the start, the linear momentum (P) of the system is equal to:

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3 years ago

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vova2212 [387]

Answer:

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