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cupoosta [38]
3 years ago
15

The answer to these please!

Mathematics
2 answers:
asambeis [7]3 years ago
5 0
Attachedd is the answer
Download docx
igomit [66]3 years ago
4 0
\sqrt[4]{(4a^{2})^{6}} = \sqrt[4]{4096a^{12}} = 8a^{3}

\sqrt[7]{(b^{\frac{5}{3}})^{8}} = \sqrt[7]{b^\frac{40}{3}} = b^{\frac{40}{21}} = \sqrt[21]{b^{40}} = \sqrt[21]{b^{21} * b^{19}} = \sqrt[21]{b^{21}} \sqrt[21]{b^{19}} = b\sqrt[21]{b^{19}}

\sqrt[3]{\frac{c^{9}}{c^{3}}} = \sqrt[3]{c^{6}} = c^{2}

\sqrt[3]{27d^{6} * 8d^{-4}} = \sqrt[3]{27d^{6} * \frac{8}{d^{4}}} = \sqrt[3]{216d^{2}} = 6\sqrt[3]{d^{2}} = 6d^{\frac{2}{3}}
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Which of the following points is the solution of the inequality <br><img src="https://tex.z-dn.net/?f=y%20%3C%20%20-%20%20%7Cx%7
Harman [31]

Answer:

(1,0)

Step-by-step explanation:

Absolute value is represented by using these bars → ║.

║= number of units from 0.

This equation says that whatever number is in the absolute value bars , x , is greater than y.

4 0
3 years ago
Read 2 more answers
Consider the function below. f(x) = ln(x4 + 27) (a) Find the interval of increase. (Enter your answer using interval notation.)
andrezito [222]

Answer:

a) The function is constantly increasing and is never decreasing

b) There is no local maximum or local minimum.

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

f(x) = ln(x^4 + 27)

f'(x) = 1/(x^2 + 27)

Now we take the derivative and solve for zero to find the local max and mins.

f'(x) = 1/(x^2 + 27)

0 = 1/(x^2 + 27)

Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.

6 0
3 years ago
Need help with math problems give 5 stars and good rating if you do a math problem
Zepler [3.9K]

Answer: I cant see the full question but I would say figure D

Step-by-step explanation:

30/20 in half is 15/10

also between 12/8 and 18/12 is 15/10

6 0
2 years ago
Someone please help
AleksandrR [38]

Replace y with 31:

31 = 7x -4

Add 4 to both sides:

35 = 7x

Divide both sides by 7:

x = 5

Input x = 5

6 0
3 years ago
Round 345276 to the nearest thousand
TiliK225 [7]
Since there is no decimal point, the answer is 345276.
8 0
3 years ago
Read 2 more answers
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