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cupoosta [38]
3 years ago
15

The answer to these please!

Mathematics
2 answers:
asambeis [7]3 years ago
5 0
Attachedd is the answer
Download docx
igomit [66]3 years ago
4 0
\sqrt[4]{(4a^{2})^{6}} = \sqrt[4]{4096a^{12}} = 8a^{3}

\sqrt[7]{(b^{\frac{5}{3}})^{8}} = \sqrt[7]{b^\frac{40}{3}} = b^{\frac{40}{21}} = \sqrt[21]{b^{40}} = \sqrt[21]{b^{21} * b^{19}} = \sqrt[21]{b^{21}} \sqrt[21]{b^{19}} = b\sqrt[21]{b^{19}}

\sqrt[3]{\frac{c^{9}}{c^{3}}} = \sqrt[3]{c^{6}} = c^{2}

\sqrt[3]{27d^{6} * 8d^{-4}} = \sqrt[3]{27d^{6} * \frac{8}{d^{4}}} = \sqrt[3]{216d^{2}} = 6\sqrt[3]{d^{2}} = 6d^{\frac{2}{3}}
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Step-by-step explanation:

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7 0
3 years ago
Select the two binomials that are factors of this trinomial x2+10x+16
Zigmanuir [339]

So for this trinomial, I will be factoring by grouping. Firstly, what two terms have a product of 16x^2 and a sum of 10x? That would be 8x and 2x. Replace 10x with 2x + 8x:

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<u>Now you can rewrite this as (x+8)(x+2) , which is your final answer.</u>

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That’s the answer
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Answer:

The answer is

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