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n200080 [17]
2 years ago
6

If e^(xy) = 2, then what is dy/dx at the point (1, ln2)?

Mathematics
1 answer:
love history [14]2 years ago
3 0
E^(xy) = 2
(xdy/dx + y)e^(xy) = 0

At point (1, ln2), dy/dx + ln2 = 0
dy/dx = -ln2
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