Answer:
Molar enthalpy change, the enthalpy change for one mole of a pure substance
Explanation: i think
Answer:
When experiments are carried out or research is done in a certain field of knowledge the scientist at first hypothesise certain knowledge or make theoretical hypotheses about that field of knowledge.
And then conduct the experiment or research to derive certain conclusions and get answers which they can apply on the hypothesis made or on the previous knowledge they have and thereby confirm or negate the hypothesis.
When two scientists are working on similar experiment and they tend to differ in the conclusions drawn by the result, as they get from experiment then it is called as confirmation bias among the scientists.
Answer:
470 °C
Explanation:
This looks like a case where we can use Charles’ Law:
Data:
V₁ = 20 L; T₁ = 100 °C
V₂ = 40 L; T₂ = ?
Calculations:
(a) Convert the temperature to kelvins
T₁ = (100 + 273.15) K = 373.15 K
(b) Calculate the new temperature
Note: The answer can have only two significant figures because that is all you gave for the volumes.
(c) Convert the temperature to Celsius
T₂ = (750 – 273.15) °C = 470 °C
According to the report of US Environmental Protection
Agency, majority of large dose radiation exposure comes from natural background
radiation sources particularly the radioactive gases radon and thoron. This two
gases form when naturally occurring elements decay. However in the case of
man-made sources, the largest dose comes from medical x-rays.
Answer:
The answer to the question above is
The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C = 29.36 kJ
Explanation:
The given variables are
ΔHfus = 7.27 kJ/mol
Cliq = 2.16 J/g°C
Cgas = 1.29 J/g°C
Csol = 1.65 J/g°C
Tmelting = -95.0°C.
Initial temperature = -154.0°C
Final temperature = -42.0°C?
Mass of acetone = 87.1 g
Molar mass of acetone = 58.08 g/mol
Solution
Heat required to raise the temperature of solid acetone from -154 °C to -95 °C or 59 °C is given by
H = mCsolT = 87.1 g* 1.65 J/g°C* 59 °C = 8479.185 J
Heat required to melt the acetone at -95 °C = ΔHfus*number of moles =
But number of moles = mass÷(molar mass) = 87.1÷58.08 = 1.5
Heat required to melt the acetone at -95 °C =1.5 moles*7.27 kJ/mol = 10.905 kJ
The heat required to raise the temperature to -42 degrees is
H = m*Cliq*T = 87.1 g* 2.16 J/g°C * 53 °C = 9971.21 J
Total heat = 9971.21 J + 10.905 kJ + 8479.185 J = 29355.393 J = 29.36 kJ
The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C is 29.36 kJ
